YT14-先来练练手之爬动的蠕虫

An inch worm is at the bottom of a well n inches deep. It has enough energy to climb u inches every minute, but then has to rest a minute before climbing again. During the rest, it slips down d inches. The process of climbing and resting then repeats. How long before the worm climbs out of the well? We'll always count a portion of a minute as a whole minute and if the worm just reaches the top of the well at the end of its climbing, we'll assume the worm makes it out.

There will be multiple problem instances. Each line will contain 3 positive integers n, u and d. These give the values mentioned in the paragraph above. Furthermore, you may assume d

10 2 1
20 3 1
0 0 0

17
19

#include   
using namespace std;  
int main()  
{  
    int n,u,d;  
    while(cin>>n>>u>>d)  
    {  
        if(n==0&&u==0&&d==0) 
            break;  
        else  
        {  
            if(((n-u)%(u-d))==0)  
                cout<<1+2*((n-u)/(u-d))<