将数组转换为散列的键-Turnanarrayintokeysforhash

2  

I'm a fan of simple, and I can never remember exactly how crazy things #inject or Hash constructor arguments work.

我是simple的粉丝，我从来都不记得#inject或Hash构造函数参数是如何工作的。

array = [1, 2, 3, 4]
hash = {}

array.each do |obj|
  hash[obj.to_s] = 0
end

puts hash.inspect # {"1"=>0, "2"=>0, "3"=>0, "4"=>0}

8  

The standard approach is Hash[...]:

标准的方法是哈希[…]:

Hash[xs.map { |x| [x.to_s, 0] }]

Or Enumerable#mash if you happen to use Facets. I cannot think of something more concise and declarative:

或者如果您碰巧使用了facet，请使用Enumerable。我想不出比这更简明扼要的了:

xs.mash { |x| [x.to_s, 0] }

4  

array.inject({}) { | a, e | a[e.to_s] = 0; a }

or in a more clean way (thanks to tokland, see the discussion in the comments)

或者用更干净的方式(感谢tokland，请参阅评论中的讨论)

array.inject({}) { | a, e | a.update(e.to_s => 0) }

0  

Okay, in reality, I'd use each_with_object, but posting this since it's more fun.

好的，实际上，我应该使用each_with_object，但是发布这个更有趣。

ary = *1..4

hash = Hash[ary.zip ary.dup.fill 0]

hash # => {1=>0, 2=>0, 3=>0, 4=>0}