PAT1146TopologicalOrder

This is a problem given in the Graduate Entrance Exam in 2018: Which of the following is NOT a topological order obtained from the given directed graph? Now you are supposed to write a program to test each of the options.

Input Specification:

Each input file contains one test case. For each case, the first line gives two positive integers N (≤ 1,000), the number of vertices in the graph, and M (≤ 10,000), the number of directed edges. Then M lines follow, each gives the start and the end vertices of an edge. The vertices are numbered from 1 to N. After the graph, there is another positive integer K (≤ 100). Then K lines of query follow, each gives a permutation of all the vertices. All the numbers in a line are separated by a space.

Output Specification:

Print in a line all the indices of queries which correspond to "NOT a topological order". The indices start from zero. All the numbers are separated by a space, and there must no extra space at the beginning or the end of the line. It is graranteed that there is at least one answer.

Sample Input:

6 8

1 2

1 3

5 2

5 4

2 3

2 6

3 4

6 4

5

1 5 2 3 6 4

5 1 2 6 3 4

5 1 2 3 6 4

5 2 1 6 3 4

1 2 3 4 5 6

Sample Output:

3 4

#include //水题， 考虑入度即可
#include
using namespace std;
int main(){
int n, m;
cin>>n>>m;
vector> v(n+1);
vector indegree(n+1, 0);
vector ans;
for(int i=0; i int s, e;
cin>>s>>e;
v[s].push_back(e);
indegree[e]++;
}
int k, a;
cin>>k;
for(int i=0; i vector t=indegree;
int flag=0;
for(int j=0; j cin>>a;
if(t[a]!=0) flag=1;
for(int p=0; p t[v[a][p]]--;
}
if(flag==1) ans.push_back(i);
}
for(int i=0; i i==0?cout< return 0;
}