OpenGL忽略四边形并使它们成为三角形

你的着色器甚至没有编译.当您声明矩阵制服时,则使用名称model2D,view2D并且projection2D:

uniform mat4 view2D;
uniform mat4 model2D;
uniform mat4 projection2D;

但是当你使用矩阵时,你使用名称view,model并projection:

gl_Position = projection * view * model * vec4(vertex.xy, 0.0, 1.0);

我建议检查着色器对象是否已成功编译以及程序对象是否成功链接.

如果可以通过glGetShaderiv和参数检查着色器的编译成功GL_COMPILE_STATUS.

例如

GLuint shaderObj = .... ;
glCompileShader( shaderObj );

GLint status = GL_TRUE;
glGetShaderiv( shaderObj, GL_COMPILE_STATUS, &status );
if ( status == GL_FALSE )
{
    GLint logLen;
    glGetShaderiv( shaderObj, GL_INFO_LOG_LENGTH, &logLen );
    std::vectorlog( logLen );
    GLsizei written;
    glGetShaderInfoLog( shaderObj, logLen, &written, log.data() );
    std::cout <<"compile error:" <

如果程序的链接成功,则可以通过glGetProgramiv参数进行检查GL_LINK_STATUS.

例如

GLuint progObj = ....;
glLinkProgram( progObj );

GLint status = GL_TRUE;
glGetProgramiv( progObj, GL_LINK_STATUS, &status );
if ( status == GL_FALSE )
{
    GLint logLen;
    glGetProgramiv( progObj, GL_INFO_LOG_LENGTH, &logLen );
    std::vectorlog( logLen );
    GLsizei written;
    glGetProgramInfoLog( progObj, logLen, &written, log.data() );
    std::cout  <<"link error:" <