查找Interface实例后面的具体类型-FindingtheConcreteTypebehindanInterfaceinstance

Type objectType = myObject.GetType();

Should still give you the concrete type, according to your example.

根据你的例子,还应该给你具体的类型。

What are you doing is really bed design but you don't have to use reflection you can check it like this

你在做什么是真正的床设计,但你不必使用反射,你可以像这样检查它

void PerformAction(object myObject)
{
    B objectType = myObject as B;   // Here is where I get typeof(IA)
    if ( objectType != null )
    {
        //use objectType.b
    }
    else
    {
       //Same with A 
    }
    // snip - other actions on objectType
}

I have to agree about the bad design. If you have an interface, it should be because you need to utilize some common functionality without caring what the concrete implementation is. Given you're example, it sounds like the PerformAction method should actually be a part of the interface:

我必须同意糟糕的设计。如果你有一个接口,应该是因为你需要利用一些常见的功能而不关心具体的实现。举个例子,听起来像PerformAction方法实际上应该是接口的一部分:

public interface IA
{
    int a { get; set; }
    void PerformAction();
}

public class B: IA
{
    public int a { get; set; }
    public int b { get; set; }

    public void PerformAction()
    {
        // perform action specific to B
    }
}

public class C : IA
{
    public int a { get; set; }
    public int c { get; set; }

    public void PerformAction()
    {
        // perform action specific to C
    }
}

void PerformActionOn(IA instance)
{
    if (instance == null) throw new ArgumentNullException("instance");

    instance.PerformAction();

    // Do some other common work...
}


B b = new B();
C c = new C();

PerformActionOn(b);
PerformActionOn(c);

You can never have instances of an Interface. So determining whether you are dealing with an interface or a concrete type is not possible since you will always be dealing with a concrete type. So I am not sure you question makes any sense. What exactly are you trying to do and why?

您永远不能拥有接口的实例。因此,确定您是在处理接口还是具体类型是不可能的,因为您将始终处理具体类型。所以我不确定你的问题是否有意义。你究竟想做什么以及为什么?

Maybe you are looking for the is operator

也许你正在寻找is运营商

void PerformAction(object myObject)
{
    if (myObject is B)
    {
        B myBObject = myObject as B;
        myBObject.b = 1;
    }

    if (myObject is C)
    {
        C myCObject = myObject as C;
        myCObject.c = 1;
    }

    // snip - other actions on objectType
}