作者:互粉-结局_596 | 来源:互联网 | 2023-05-24 20:29
给定数组
[
{date: '2014-01-01', a: 5, b:1},
{date: '2014-01-01', xyz: 11},
{date: '2014-10-10', qbz: 5},
{date: '2014-10-10', v: 4, q: 1, strpm: -99}
]
我想按日期分组并输出一个哈希数组
ouput = [
{date: 2014-01-01, a: 5, b:1, xyz: 11 },
{date: 2014-10-10, qbz: 5, v: 4, q: 1, strpm: -99},
]
我在Ruby中解决它并有一个解决方案,但它似乎效率低下.
def arrayt(inputarray)
outputarray=[];
inputarray.each do |x|
tindex = includes(outputarray,x[:date])
if tindex == -1
outputarray.push(x)
else
outputarray[tindex].merge!(x)
end
end
return outputarray
end
def includes(array,date)
array.each_with_index do |temp,index|
if date==temp[:date]
return index
end
end
return -1
end
任何有关更优雅的解决方案的帮助将不胜感激
1> sawa..:
[
{date: '2014-01-01', a: 5, b:1},
{date: '2014-01-01', xyz: 11},
{date: '2014-10-10', qbz: 5},
{date: '2014-10-10', v: 4, q: 1, strpm: -99}
]
.group_by(&:first).map{|_, v| v.inject(:merge)}