使用python时间处理方法

先将sep 格式时间转化成 后面一个格式的时间样子，没有找到相关函数，于是自己简单的写了个程序，仅记于此，以备查询

代码如下：

# -*- coding: utf-8 -*- 
from datetime import date
from datetime import datetime
from datetime import timedelta
 
# # #如果是返回当前时间，可以简单的写成
# # time.localtime()
# # #这个返回UTC时间
# # time.gmtime()
# lt = time.localtime()
# tm = time.gmtime()
# ft = time.strftime(&＃39;%Y-%m-%d %H-%M&＃39;,lt)
# ft2 = time.strftime(&＃39;%Y-%m-%d %H:%M&＃39;,tm)
# print ft, ft2
# print &＃39;--------------------------------------------------------&＃39;
# now = datetime.datetime.now()
# now = now.replace(day = 1)
# print now
# print now.time()
#
# mytime = [&＃39;2014-09-06 20:19&＃39;]
# #mytime2 = &＃39;2014-10-09 14:32&＃39;
# str = "".join(mytime)
# print str
# retime  = datetime.strptime(str,&＃39;%Y-%m-%d %H:%M&＃39;)
# print retime
# retime = retime +timedelta(hours = 8)
# print retime
#
# tdtime = datetime.now()
# print tdtime
# if retime <= tdtime - timedelta(days = 7):
#     print "too early"
#
# #Sep 06, 2014 19:30
 
mOnthdic= {&＃39;Jan&＃39;:&＃39;01&＃39;, &＃39;Feb&＃39;:&＃39;02&＃39;, &＃39;Mar&＃39;:&＃39;03&＃39;, &＃39;Apr&＃39;:&＃39;04&＃39;, &＃39;May&＃39;:&＃39;05&＃39;, &＃39;Jun&＃39;:&＃39;06&＃39;, &＃39;Jul&＃39;:&＃39;07&＃39;, &＃39;Aug&＃39;:&＃39;08&＃39;, &＃39;Sep&＃39;:&＃39;09&＃39;, &＃39;Oct&＃39;:&＃39;10&＃39;, &＃39;Nov&＃39;:&＃39;11&＃39;, &＃39;Dec&＃39;:&＃39;12&＃39;}
def time_format(timestr):
    timestr = timestr.replace(&＃39;,&＃39;,&＃39;&＃39;)
    #print timestr
    timelist = timestr.split()
    #print timelist
    mon = "".join(timelist[0])
    #print  mon
    timelist[0] = monthdic[mon]
    #print timelist
    mytime = "".join(timelist[2])+&＃39;-&＃39;+"".join(timelist[0])+&＃39;-&＃39;+"".join(timelist[1])+&＃39; &＃39;+ "".join(timelist[3])
    return mytime
if name == &＃39;main&＃39;:
    timestr = &＃39;Sep 06, 2014 19:30&＃39;
    str = time_format(timestr)
    print str      
    mytime  = datetime.strptime(str,&＃39;%Y-%m-%d %H:%M&＃39;) 
    print mytime
    mytime = mytime +timedelta(hours = 8)
    print mytime  
    tdtime = datetime.now()
    print tdtime
    if mytime <= tdtime - timedelta(days = 7):
        print "too early"

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