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sql中字符串分割函数

在sql中没有系统带的的字符分割函数,我们利用了一些功能字了一个分割函数有需要的同学可以参考一下。

在sql中没有系统带的的字符分割函数,我们利用了一些功能字了一个分割函数有需要的同学可以参考一下。

代码如下

SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO

/*by kudychen 2011-9-28 */
CREATE function [dbo].[SplitString]
(
@Input nvarchar(max), --input string to be separated
@Separator nvarchar(max)=',', --a string that delimit the substrings in the input string
@RemoveEmptyEntries bit=1 --the return value does not include array elements that contain an empty string
)
returns @TABLE table
(
[Id] int identity(1,1),
[Value] nvarchar(max))
as
begin
declare @Index int, @Entry nvarchar(max)
set @Index = charindex(@Separator,@Input)

while (@Index>0)
begin
set @Entry=ltrim(rtrim(substring(@Input, 1, @Index-1)))

if (@RemoveEmptyEntries=0) or (@RemoveEmptyEntries=1 and @Entry<>'')
begin
insert into @TABLE([Value]) Values(@Entry)
end

set @Input = substring(@Input, @Index+datalength(@Separator)/2, len(@Input))
set @Index = charindex(@Separator, @Input)
end

set @Entry=ltrim(rtrim(@Input))
if (@RemoveEmptyEntries=0) or (@RemoveEmptyEntries=1 and @Entry<>'')
begin
insert into @TABLE([Value]) Values(@Entry)
end
return

end

Test Code:

代码如下

declare @str1 varchar(max), @str2 varchar(max), @str3 varchar(max)

set @str1 = '1,2,3'
set @str2 = '1###2###3'
set @str3 = '1###2###3###'

[Value] from [dbo].[SplitString](@str1, ',', 1)
select [Value] from [dbo].[SplitString](@str2, '###', 1)
select [Value] from [dbo].[SplitString](@str3, '###', 0)

Code:

代码如下

SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO

/*by kudychen 2011-9-28 */
CREATE function [dbo].[SplitString]
(
@Input nvarchar(max), --input string to be separated
@Separator nvarchar(max)=',', --a string that delimit the substrings in the input string
@RemoveEmptyEntries bit=1 --the return value does not include array elements that contain an empty string
)
returns @TABLE table
(
[Id] int identity(1,1),
[Value] nvarchar(max))
as
begin
declare @Index int, @Entry nvarchar(max)
set @Index = charindex(@Separator,@Input)

while (@Index>0)
begin
set @Entry=ltrim(rtrim(substring(@Input, 1, @Index-1)))

if (@RemoveEmptyEntries=0) or (@RemoveEmptyEntries=1 and @Entry<>'')
begin
insert into @TABLE([Value]) Values(@Entry)
end

set @Input = substring(@Input, @Index+datalength(@Separator)/2, len(@Input))
set @Index = charindex(@Separator, @Input)
end

set @Entry=ltrim(rtrim(@Input))
if (@RemoveEmptyEntries=0) or (@RemoveEmptyEntries=1 and @Entry<>'')
begin
insert into @TABLE([Value]) Values(@Entry)
end
return

end

Test Code:

代码如下

declare @str1 varchar(max), @str2 varchar(max), @str3 varchar(max)

set @str1 = '1,2,3'
set @str2 = '1###2###3'
set @str3 = '1###2###3###'

select [Value] from [dbo].[SplitString](@str1, ',', 1)
select [Value] from [dbo].[SplitString](@str2, '###', 1)
select [Value] from [dbo].[SplitString](@str3, '###', 0)

吐了个 "CAO" !
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