C将字符串解析为没有任何lib函数的字符数组-Cparsingstringtoarrayofcharswithoutanylibfunctions

What I am trying to do, is parse string, containing spaces to array of arrays of chars. So if input was "ab cd ef", I want my array to be array[0]==ab, array[1]==cd,array[2]==ef. I hope that that makes it clear. Problem however is that i cant use any lib functions. No string.h, no fget, just scanf and printf. Here is snipplet of my code:

我正在尝试做的是解析字符串，包含字符数组数组的空格。因此，如果输入是“ab cd ef”，我希望我的数组是数组[0] == ab，数组[1] == cd，数组[2] == ef。我希望这说清楚。但问题是我无法使用任何lib函数。没有string.h，没有fget，只有scanf和printf。这是我的代码的snipplet：

char word[25] = "";
char *words[25];

for (int i = 0; i <= find_length(input); i++){
    if(input[i] == ' ' || i == find_length(input)){
        words[position] = word;
        printf("%s%d ",words[position], position);
        position++;
        counter = 0;
        word[0] = '\0';
    }
    else{
        word[counter] = input[i];
        counter++;
    }
}

position = 0;

while(counter <5){
    printf("%s%d ",words[position], position);
    counter++;
}

First I parse string into individual words and then I try to put them into array. I hope that my logic is correct. So the problem is, that first printf (one in for loop) prints proper values and their positions. However second printf (which is only to make sure that string was parsed properly) prints just 0. So for example input "ab cd ef" gives:

首先，我将字符串解析为单个单词，然后我尝试将它们放入数组中。我希望我的逻辑是正确的。所以问题是，第一个printf（for循环中的一个）打印正确的值及其位置。然而，第二个printf（仅用于确保正确解析字符串）仅打印0.因此，例如输入“ab cd ef”给出：

ab0 cd1 ef2 0 0 0 0 0

ab0 cd1 ef2 0 0 0 0 0

I suspect that problem is that I am not adding values to the array of arrays, just assigning pointers. And since I dump "word", they point to nothing. If that is correct, how do I assign values instead of pointers?

我怀疑问题是我没有为数组数组添加值，只是分配指针。因为我倾倒“字”，他们指向什么都没有。如果这是正确的，我如何分配值而不是指针？

Of course this assumption might be wrong, if so could you point me to my mistake and how to fix it? Thank you.

当然这个假设可能是错误的，如果是这样，你能否指出我的错误以及如何解决它？谢谢。

PS: I know that I should strcpy value of string not = it, but as I said, I cant use any lib functions other than scanf and printf (find_length is my own function)

PS：我知道我应该strcpy string的值not = it，但正如我所说，我不能使用除scanf和printf之外的任何lib函数（find_length是我自己的函数）

2 个解决方案

for (int i = 0; i <= find_length(input); i++){
    if(input[i] == ' ' || i == find_length(input)){
        words[position] = word;
        printf("%s%d ",words[position], position);
        position++;
        counter = 0;
        word[0] = '\0';
    }

for (int i = 0; i <= find_length(input); i++) {
    if(input[i] == ' ' || i == find_length(input)) {
    words[position] = malloc(sizeof(char) * (counter + 1));
        for (int j = 0; j 

position = 0;

while(position <5) {
    printf("%s%d ", words[position], position);
    position++;
}