如何在引号前没有反斜杠的python石墨烯解析器中返回json

我在python(Flask + Graphene)中有一个后端服务器,我需要返回一个这样的JSON对象:

{
      's1': "Section 1",
      's2': "Section 2",
      's3': "Section 3",
      's4': "Section 4"
}

解析器如下所示:

 questiOnnaire= graphene.types.json.JSONString(
        description='JSON result test')

    def resolve_questionnaire(self, info: graphql.ResolveInfo):
        sectiOns= {
          's1': "Section 1",
          's2': "Section 2",
          's3': "Section 3",
          's4': "Section 4"
        }

        print(json.dumps(sections))
        return sections

在控制台中我看到了print(json.dumps(sections))我期望的结果:

user-api_1  | {"s1": "Section 1", "s2": "Section 2", "s3": "Section 3", "s4": "Section 4"}

但在GraphiQL中,我看到所有带反斜杠的引号:

当我更改为时return sections,return json.dumps(sections)我得到如下结果:

问题是如何在石墨烯解析器中正确返回JSON对象？ 我知道有像这里使用的json.replace方法,但我相信我只是以错误的方式生成/传递对象.

你的初步结果

{
  "data": {
    "questionnaire": "{\"s1\": \"Section 1\", \"s2\": \"Section 2\", \"s3\": \"Section 3\", \"s4\": \"Section 4\"}"
  }
}

是预期的行为.毕竟,questionnaire解析为JSON 字符串.由于它是一个字符串,因此必须双引号,因此必须对其内部引用进行转义.这符合JSON的标准.

要使用该字符串,必须在data.questionnaire对象上运行某种JSON解析器.例如,在Javascript中,它会是这样的:

var data;
// Fetching logic to get the data object from your GraphQL server
var sectiOns= JSON.parse(data.questionaire);

// Now you can access its objects
console.log(sections.s1) // Should print "Section 1" on the dev console

import graphene

# Our new model
class Section(graphene.ObjectType):
    key = graphene.String()        # dictionary key
    header = graphene.String()     # dictionary value

# Your previous schema with modifications
class Query(graphene.ObjectType):
    # questiOnnaire= graphene.types.json.JSONString(description='JSON result test')

    # Return a list of section objects
    questiOnnaire= graphene.List(Section)

    def resolve_questionnaire(self, info: graphql.ResolveInfo):
        sectiOns= {
          's1': "Section 1",
          's2': "Section 2",
          's3': "Section 3",
          's4': "Section 4"
        }

        sections_as_obj_list = [] # Used to return a list of Section types

        # Create a new Section object for each item and append it to list
        for key, value in sections.items(): # Use sections.iteritems() in Python2
            section = Section(key, value) # Creates a section object where key=key and header=value
            sections_as_obj_list.append(section)

        # return sections
        return sections_as_obj_list

query {
  questionnaire {
    key
    header
  }
}

{
  "data" {
    "questionnaire": [
      {
        "key": "s1",
        "header": "Section 1"
      },
      {
        "key": "s2",
        "header": "Section 2"
      },
      {
        "key": "s3",
        "header": "Section 3"
      },
      {
        "key": "s4",
        "header": "Section 4"
      },
    ]
  }
}