Python实现暴力破解有密码的zip文件的方法

import itertools

def allkeyword(dic,num):
  allkey1 = itertools.product(dic,repeat=num)
  allkey2 = (''.join(i) for i in allkey1)
  return allkey2

dictiOnaries= ['1', '2']
print(list(allkeyword(dictionaries,4)))

import zipfile

try:
  ZIPFILE = zipfile.ZipFile(r'D:\123\1.zip')
  ZIPFILE.extractall(path=r'D:\12',pwd=b'1234')
  print("解压成功")

except:
  print("解压失败")

import zipfile
import itertools


dictiOnaries= ['1', '2', '3', '4','5','6','7','8','9','0',
        'a','b','c','d','e','f','g','h','i','j','k',
        'l','m','n','o','p','q','r','s','t','u','v',
        'w','x','y','z']     #组成破解字典的关键字符（可以按照自己需求添加）


def allkeyword():      #排列出字符所有4个字符的组合
  allkey1 = itertools.product(dictionaries,repeat=4)
  allkey2 = (''.join(i) for i in allkey1)
  return allkey2


def trypassword (password):
  try:
    ZIPFILE = zipfile.ZipFile(r'D:\123\1.zip')  #定义对象，相当于定义一个压缩文件1.zip
    ZIPFILE.extractall(path=r'D:\12',pwd=password.encode('utf-8')) 
    print(f"解压成功,正确密码为：{password}")
    return True
  except:
    print(f"解压失败,尝试密码为：{password}")
    return False

#用trypassword函数返回的True或者Flase来判定程序是否终止。
for pwd in allkeyword() :  
  if trypassword(pwd):
    break