Mock框架返回具有不同名称和类型的类-Mockframeworksreturnsclasswithdifferentnameandtype

2  

I just experimented with an existing test of my own, and by changing the interface namespace name from one that exists to one that doesn't exist, I got exactly the same as what you describe (using phpunit). My mock object had the class name Mock_ViewInterface_c755461e. When I change it back to the correct interface name, it works fine.

我刚刚尝试了一个我自己的现有测试，通过将接口名称空间名称空间从存在的名称空间更改为不存在的名称空间，我得到了与您描述的完全相同的结果(使用phpunit)。我的mock对象的类名为Mock_ViewInterface_c755461e。当我将它更改为正确的接口名称时，它可以正常工作。

Therefore I would say that either:

因此，我要说:

1. You are trying to use an interface name that doesn't exist (e.g. a typo or missing namespace component).
2. 您正在尝试使用一个不存在的接口名称(例如，输入错误或缺少名称空间组件)。
3. Your library code isn't being loaded for some reason, e.g. autoloading is not setup correctly in your unit test bootstrap.
4. 由于某些原因，您的库代码没有被加载，例如，在单元测试引导中没有正确地设置自动加载。

-2  

You need use a special function to check base class. Somthing like this:

您需要使用一个特殊的函数来检查基类。事情是这样的:

$mock = $this->getMock('MyClass');
$this->assertInstanceOf('MyClass', $mock);