检查数组中的最小元素是否小于或等于每隔一个元素的一半

// C++ implementation to Check if the minimum element in the
// array is greater than or equal to half of every other elements
#include <bits/stdc++.h>
using namespace std;
// Function to Check if the minimum element in the array is
// greater than or equal to half of every other element
void checkMin(int arr[], int len)
{
    // Initialise the variables to store
    // smallest and second smallest
    int smallest = INT_MAX, secondSmallest = INT_MAX;
    for (int i = 0; i < len; i++) {
        // Check if current element is smaller than smallest,
        // the current smallest will become secondSmallest
        // and current element will be the new smallest
        if (arr[i] < smallest) {
            secondSmallest = smallest;
            smallest = arr[i];
        }
        // Check if current element is smaller than
        // secondSmallest simply update the latter
        else if (arr[i] < secondSmallest) {
            secondSmallest = arr[i];
        }
    }
    if (2 * smallest <= secondSmallest)
        cout << "Yes";
    else
        cout << "No";
}
// Driver code
int main()
{
    int arr[] = { 2, 3, 4, 5 };
    int len = sizeof(arr) / sizeof(arr[0]);
    checkMin(arr, len);
}


// Java implementation to check
// if the minimum element in the
// array is greater than or equal
// to half of every other elements
import java.util.*;
class GFG{
// Function to Check if the minimum
// element in the array is greater
// than or equal to half of every
// other elements
static void checkMin(int arr[], int len)
{
    // Initialise the variables to store
    // smallest and second smallest
    int smallest = Integer.MAX_VALUE;
    int secondSmallest = Integer.MAX_VALUE;
    for(int i = 0; i < len; i++)
    {
       // Check if current element is smaller than 
       // smallest, the current smallest will 
       // become secondSmallest and current 
       // element will be the new smallest
       if (arr[i] < smallest)
       {
           secondSmallest = smallest;
           smallest = arr[i];
       }
       // Check if current element is smaller than
       // secondSmallest simply update the latter
       else if (arr[i] < secondSmallest)
       {
           secondSmallest = arr[i];
       }
    }
    if (2 * smallest <= secondSmallest)
        System.out.print("Yes");
    else
        System.out.print("No");
}
// Driver code
public static void main(String[] args)
{
    int arr[] = { 2, 3, 4, 5 };
    int len = arr.length;
    checkMin(arr, len);
}
}
// This code is contributed by amal kumar choubey


# Python3 implementation to Check if
# the minimum element in the array
# is greater than or equal to half
# of every other element
import math
# Function to Check if the minimum element
# in the array is greater than or equal to
# half of every other element
def checkMin(arr, n):
    # Initialise the variables to store
    # smallest and second smallest
    smallest = math.inf
    secondSmallest = math.inf
    for i in range(n):
        # Check if current element is
        # smaller than smallest,
        # the current smallest will become
        # secondSmallest and current element
        # will be the new smallest
        if(arr[i] < smallest):
            secondSmallest = smallest
            smallest = arr[i]
        # Check if current element is smaller than
        # secondSmallest simply update the latter
        elif(arr[i] < secondSmallest):
            secondSmallest = arr[i]
    if(2 * smallest <= secondSmallest):
        print("Yes")
    else:
        print("No")
# Driver code
if __name__ == '__main__':
    arr = [ 2, 3, 4, 5 ]
    n = len(arr)
    checkMin(arr, n)
# This code is contributed by Shivam Singh.


// C# implementation to check
// if the minimum element in the
// array is greater than or equal
// to half of every other elements
using System;
class GFG{
// Function to Check if the minimum
// element in the array is greater
// than or equal to half of every
// other elements
static void checkMin(int []arr, int len)
{
    // Initialise the variables to store
    // smallest and second smallest
    int smallest = int.MaxValue;
    int secondSmallest = int.MaxValue;
    for(int i = 0; i < len; i++)
    {
       // Check if current element is smaller than
       // smallest, the current smallest will
       // become secondSmallest and current
       // element will be the new smallest
       if (arr[i] < smallest)
       {
           secondSmallest = smallest;
           smallest = arr[i];
       }
       // Check if current element is smaller than
       // secondSmallest simply update the latter
       else if (arr[i] < secondSmallest)
       {
           secondSmallest = arr[i];
       }
    }
    if (2 * smallest <= secondSmallest)
        Console.Write("Yes");
    else
        Console.Write("No");
}
// Driver code
public static void Main(String[] args)
{
    int []arr = { 2, 3, 4, 5 };
    int len = arr.Length;
    checkMin(arr, len);
}
}
// This code is contributed by amal kumar choubey


<script>
// Javascript implementation to check 
// if the minimum element in the
// array is greater than or equal
// to half of every other elements
// Function to Check if the minimum
// element in the array is greater
// than or equal to half of every
// other element
function checkMin(arr, len)
{
    // Initialise the variables to store
    // smallest and second smallest
    var smallest = Number.INFINITY,
        secondSmallest = Number.INFINITY;
    for(var i = 0; i < len; i++)
    {
        // Check if current element is
        // smaller than smallest, the
        // current smallest will become
        // secondSmallest and current
        // element will be the new smallest
        if (arr[i] < smallest)
        {
            secondSmallest = smallest;
            smallest = arr[i];
        }
        // Check if current element is smaller than
        // secondSmallest simply update the latter
        else if (arr[i] < secondSmallest)
        {
            secondSmallest = arr[i];
        }
    }
    if (2 * smallest <= secondSmallest)
        document.write("Yes");
    else
        document.write("No");
}
// Driver code
var arr = [ 2, 3, 4, 5 ];
var len = 4;
checkMin(arr, len);
// This code is contributed by akshitsaxenaa09
script>


No