如何在这种情况下使用Awk-HowtouseAwkinthissituation

6  

I believe this does what you want.

我相信这会做你想要的。

awk 'alen==length($1) {for (i=a;i<=$1;i++) print i}; {a=$1; alen=length(a); if (a==(i-1)) {a++}}'

When alen (the length of a) is the same as the length of the current line loop between a and $1 printing out all missing values.

当alen(a的长度)与a和$ 1之间的当前行循环的长度相同时,打印出所有缺失值。

Then set a to the new $1, alen to the length of a, and when we dealt with a missing range (when a is the same as i - 1) increment a so we don't duplicate that number (this handles cases of sequential lines like 335, 339, 350 without duplicating 339).

然后设置一个新的$ 1,alen到a的长度,当我们处理一个缺失的范围(当a与i-1相同时)增加a所以我们不重复那个数字(这处理顺序的情况)像335,339,350这样的行没有重复339)。

With credit to @fedorqui for the basic idea.

感谢@fedorqui的基本想法。

Edit: I believe this fixes the problem I noted in the comments (which I think is what @JohnB was indicating as well):

编辑:我相信这解决了我在评论中注意到的问题(我认为这也是@JohnB所指出的):

awk '{f=0; if (alen==length($1)) {for (i=a;i<=$1;i++) print i} else {f=1}} {a=$1; alen=length(a)} a==(i-1){a++} f{print; a++}'

I feel like there should be a simpler way to do that but I don't see it at the moment.

我觉得应该有一个更简单的方法来做到这一点,但我现在还没有看到它。

Edit again: The input file I ended up testing with:

再次编辑:我最终测试的输入文件:

335
339
340
345
3412
34125
666665
666668

3  

The first approach is this:

第一种方法是这样的:

$ awk 'NR%2 {a=$1; next} $1>a {for (i=a;i<=$1;i++) print i}' file
335
336
337
338
339
666665
666666
666667
666668

It can be improved as much as info and effort you put in your question :)

它可以改进你提出的问题中的信息和努力:)

Explanation

• NR%2 {a=$1; next} as NR stands for number of record (number of line in this case), NR%2 is 1 if NR is not multiple of 2. So this stores the value of the line in the variable a in the odd lines. Then, next stops processing current line.

NR%2 {a = $ 1;由于NR代表记录数(在这种情况下为行数),如果NR不是2的倍数,则NR%2为1.因此,这将变量a中的行的值存储在奇数行中。然后,下一步停止处理当前行。

• $1>a {for (i=a;i<=$1;i++) print i} in the other cases (even lines), if the value is bigger than the one that was stored, it loops from that value up to the current one, printing all the values in between.

$ 1> a {for(i = a; i <= $ 1; i ++)print i}在其他情况下(偶数行),如果该值大于存储的值,则从该值循环到当前值一,打印其间的所有值。