javascript或asp实现的判断身份证号码是否正确两种验证方法_javascript技巧

代码如下:

代码如下:

<%
Function checkIDCard(idcard) '-1为正确的身份证，否则为非法身份证

Dim Y, JYM
Dim S, M

Dim area
area = "11,12,13,14,15,21,22,23,31,32,33,34,35,36,37,41,42,43,44,45,46,50,51,52,53,54,61,62,63,64,65,71,81,82,91"
Dim ereg
Set ereg = New regexp

'地区检验
If InStr(1, area, Mid(idcard, 1, 2)) = 0 Then checkIDCard = 1: Exit Function

'身份号码位数及格式检验
Select Case Len(idcard)
Case 15
If ((CInt(Mid(idcard, 7, 2)) + 1900) Mod 4 = 0 or ((CInt(Mid(idcard, 7, 2)) + 1900) Mod 100 = 0 And (CInt(Mid(idcard, 7, 2)) + 1900) Mod 4 = 0)) Then
ereg.Pattern = "^[1-9][0-9]{5}[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|[1-2][0-9]))[0-9]{3}$" ';//测试出生日期的合法性
Else
ereg.Pattern = "^[1-9][0-9]{5}[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|1[0-9]|2[0-8]))[0-9]{3}$" ';//测试出生日期的合法性
End If
If (ereg.test(idcard)) Then
checkIDCard = -1
Else
checkIDCard = 2
End If
Case 18
'//18位身份号码检测
'//出生日期的合法性检查
If ((CInt(Mid(idcard, 7, 2)) + 1900) Mod 4 = 0 or ((CInt(Mid(idcard, 7, 2)) + 1900) Mod 100 = 0 And (CInt(Mid(idcard, 7, 2)) + 1900) Mod 4 = 0)) Then
ereg.Pattern = "^[1-9][0-9]{5}19[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|[1-2][0-9]))[0-9]{3}[0-9Xx]$" ';//闰年出生日期的合法性正则表达式
Else
ereg.Pattern = "^[1-9][0-9]{5}19[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|1[0-9]|2[0-8]))[0-9]{3}[0-9Xx]$" ';//平年出生日期的合法性正则表达式
End If
If (ereg.test(idcard)) Then
'//计算校验位
S = (CInt(Mid(idcard, 0 + 1, 1)) + CInt(Mid(idcard, 10 + 1, 1))) * 7 _
+ (CInt(Mid(idcard, 1 + 1, 1)) + CInt(Mid(idcard, 11 + 1, 1))) * 9 _
+ (CInt(Mid(idcard, 2 + 1, 1)) + CInt(Mid(idcard, 12 + 1, 1))) * 10 _
+ (CInt(Mid(idcard, 3 + 1, 1)) + CInt(Mid(idcard, 13 + 1, 1))) * 5 _
+ (CInt(Mid(idcard, 4 + 1, 1)) + CInt(Mid(idcard, 14 + 1, 1))) * 8 _
+ (CInt(Mid(idcard, 5 + 1, 1)) + CInt(Mid(idcard, 15 + 1, 1))) * 4 _
+ (CInt(Mid(idcard, 6 + 1, 1)) + CInt(Mid(idcard, 16 + 1, 1))) * 2 _
+ CInt(Mid(idcard, 7 + 1, 1)) * 1 _
+ CInt(Mid(idcard, 8 + 1, 1)) * 6 _
+ CInt(Mid(idcard, 9 + 1, 1)) * 3
Y = S Mod 11
M = "F"
JYM = "10X98765432"
M = Mid(JYM, Y + 1, 1)

If (M = Mid(idcard, 17 + 1, 1)) Then checkIDCard = -1 Else checkIDCard = 3

Else
checkIDCard = 4
End If

Case Else
checkIDCard = Len(idcard)
End Select

End Function%>