作者:手机用户2602897411 | 来源:互联网 | 2022-04-18 22:33
使用 YEAR(), MONTH(), DAY() 来获取年月日
SELECT YEAR(application_date) as years, count(1) FROM patent GROUP BY YEAR(application_date) ORDER BY years
-- YEAR(application_date) 获取年份
-- MONTH(application_date) 获取月份
-- DAY(application_date) 获取日
使用 date_format(application_date, '%Y'),可自定义日期格式
SELECT date_format(application_date, "%Y") as year, count(1) FROM patent GROUP BY date_format(application_date, "%Y")
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