javascript–从任意深度的父/子关系中的所有对象中删除特定属性

我有一个Javascript对象,表示任意深度的父子关系.如何删除所有对象的某些属性？

var persOns= [{
name: 'hans',
age: 25,
idontwantthis: {
somevalue: '123'
},
children: [{
name: 'hans sohn',
age: 8,
idontwantthiseither: {
somevalue: '456'
},
children: [{
name: 'hans enkel',
age: 2,
children: []
}]
}]
}];


我只想要属性名称,年龄和孩子,并摆脱所有其他人.新数组应如下所示：

var persOns= [{
name: 'hans',
age: 25,
children: [{
name: 'hans sohn',
age: 8,
children: [{
name: 'hans enkel',
age: 2,
children: []
}]
}]
}];


解决方法:

使用recursion并使用Array#forEach方法进行迭代,使用Object.keys获取属性名称数组的方法,使用delete删除对象的某些属性,使用delete进行检查是对象,使用Array.isArray进行检查是否为数组.

// hash map for storing properties which are needed to keep
// or use an array and use `indexOf` or `includes` method
// to check but better one would be an object
var keep = {
name: true,
age: true,
children: true
}
function update(obj, kp) {
// check its an array
if (Array.isArray(obj)) {
// if array iterate over the elment
obj.forEach(function(v) {
// do recursion
update(v, kp);
})
// check element is an object
} else if (typeof obj == 'object') {
// iterate over the object keys
Object.keys(obj).forEach(function(k) {
// check key is in the keep list or not
if (!kp[k])
// if not then delete it
delete obj[k];
else
// otherwise do recursion
update(obj[k], kp);
})
}
}
update(persons, keep);


var persOns= [{
name: 'hans',
age: 25,
idontwantthis: {
somevalue: '123'
},
children: [{
name: 'hans sohn',
age: 8,
idontwantthiseither: {
somevalue: '456'
},
children: [{
name: 'hans enkel',
age: 2,
children: []
}]
}]
}];
var keep = {
name: true,
age: true,
children: true
}
function update(obj, kp) {
if (Array.isArray(obj)) {
obj.forEach(function(v) {
update(v, kp);
})
} else if (typeof obj == 'object') {
Object.keys(obj).forEach(function(k) {
if (!kp[k])
delete obj[k];
else
update(obj[k], kp);
})
}
}
update(persons, keep);
console.log(persons);