// map 基本使用
let map = new Map();
map.set(‘name‘,‘WHQ‘);
map.set(‘age‘,24);
map.set(‘未婚‘,true);
console.log(map.get(‘name‘));
console.log(map.get(‘age‘));
console.log(map.get(‘未婚‘));

// key是对象
let obj = {};
map.set(obj,‘对象‘);
console.log(map.get(obj));
//
// key是函数
let func =function (){};
map.set(func,‘函数‘);
console.log(map.get(func))
// key 是NaN
map.set(NaN,‘NaN‘)
console.log(map.get(NaN))
console.log(map.get(Number(‘aaa‘)))

// map迭代
// for .. of
for (let [key,value] of map) {
console.log(key,value)
}
// foreach
map.forEach(function(value, key, map){
console.log(value,key,map.get(key))
})
// 所有的key
for (let key of map.keys()){
console.log(key)
}
// 所有的值
for (let value of map.values()) {
console.log(value)
}

// Map对象操作
// Map与Array转换
// 数组转map
let arr = [[‘k1‘,‘v1‘],[‘k2‘,‘v2‘]]
let map2 = new Map(arr)
console.log(map2)
// map转数组
let arr2=Array.from(map2)
console.log(arr2)
// map合并 ...三点符号可以直接取值
let map3=new Map([...map,...map2])
console.log(map3)

// set里面的value值是唯一的
// map允许有相同的value值
let myMap = new Map();
myMap.set(‘no001‘,‘张三‘);
myMap.set(‘no002‘,‘李四‘);
myMap.set(‘no003‘,‘张三‘);
console.log(myMap)
// set里面的value值是唯一的
let mySet=new Set();
mySet.add(‘张三‘)
mySet.add(‘李四‘)
mySet.add(‘张三‘)
console.log(mySet)

// set遍历
// for ... of
for (let value of mySet.values()) {
console.log(value)
}
// forEach遍历
mySet.forEach(function (value) {
console.log(value)
})

//Set 转数组
let arr3 =[[‘k1‘,‘v1‘],[[‘k2‘,‘v2‘]]];
let set3 = new Set(arr3)
console.log(set3)
//直接三点运算符,转数组
let arr4 = [...set3]
console.log(arr4)

// 数组去重
let arr5 = [1,3,5,3,6];
let set6=new Set(arr5)
let arr6=[...set6]
console.log(arr6)
// 求并集
let a = new Set([1, 2, 3]);
let b = new Set([4, 3, 2]);
let union = new Set([...a,...b]);// {1, 2, 3, 4}
console.log(‘求并集‘)
console.log(union)
// 求交集
let a2 = new Set([1, 2, 3]);
let b2 = new Set([4, 3, 2]);
let intersect = new Set([...a].filter(x =>b2.has(x)));// {2, 3}
console.log(‘求交集‘)
console.log(intersect)
//求差集
let a3 = new Set([1, 2, 3]);
let b3 = new Set([4, 3, 2]);
let differenceA3 = new Set([...a3].filter(x => !b3.has(x)));// {1}
let differenceB3 = new Set([...b3].filter(x => !a3.has(x))); //{4}
console.log(‘求差集‘)
console.log(differenceA3)
console.log(differenceB3)