asp.netTreeView与XML配合使用v1.1

刚我在做Tree view 绑定时自己摸索了一下，网上有人说TreeView绑定数据源，用什么递归绑定啥的，我不想看了，就自己试着写了一个

我是这样做的，如果有什么问题请大神指导，我是菜鸟额..

1:页面TreeView 叫tvFunction

2:新建 adminFunction.xml

?xml version="1.0" encoding="utf-8" ?
functions
function name="商品发布" url="~/page/leaves/leave.aspx"
subfunction name="添加商品" url="~/page/leaves/leave.aspx"
/subfunction
subfunction name="添加商品" url="~/page/leaves/leave.aspx"
/subfunction
/function
function name="留言发布" url="~/page/leaves/leave.aspx"
subfunction name="添加留言" url="~/page/leaves/leave.aspx"
/subfunction
subfunction name="修改留言" url="~/page/leaves/leave.aspx"
/subfunction
/function
/functions

3：页面绑定

/// summary
/// 初始化功能树结构
/// /summary
private void InitFunction()
{
XmlDocument xmldoc = new XmlDocument();
string xmlPath = "~/adminFunction.xml";
xmlPath = Server.MapPath(xmlPath);
xmldoc.Load(xmlPath);
XmlNode root = xmldoc.DocumentElement;
foreach (XmlNode node in root.ChildNodes)
{
//获取父节点的信息显示(轻狂-书生)
XmlElement x1 = node as XmlElement;
string name = x1.GetAttribute("name");
string url = x1.GetAttribute("url");
TreeNode tn = new TreeNode();
tn.Text = name;
tn.NavigateUrl = url;
foreach (XmlNode subnode in x1.ChildNodes)
{
XmlElement subxmlEmt = subnode as XmlElement;
string subname = subxmlEmt.GetAttribute("name");
string suburl = subxmlEmt.GetAttribute("url");
TreeNode subtn = new TreeNode();
subtn.Text = subname;
subtn.NavigateUrl = suburl;
tn.ChildNodes.Add(subtn);
}
tvFunction.Nodes.Add(tn);
}
}

4：显示效果

感觉效果还行，请问我这样做好么？有什么更好的方式么？请指教，谢谢了..

----修改后的版本

根据大神们的指导，我晚上回来试了下递归（全手打）

方法如下

1：XML改为

?xml version="1.0" encoding="utf-8" ?
functions
function name="商品发布" url="~/page/leaves/leave.aspx"
subfunction name="添加商品" url="~/page/leaves/leave.aspx"
subfunction1 name="" url="~/page/leaves/leave.aspx"
subfunction2 name="" url="~/page/leaves/leave.aspx"
/subfunction2
subfunction2 name="" url="~/page/leaves/leave.aspx"
/subfunction2
/subfunction1
subfunction1 name="" url="~/page/leaves/leave.aspx"
/subfunction1
/subfunction
subfunction name="添加商品" url="~/page/leaves/leave.aspx"
/subfunction
/function
function name="留言发布" url="~/page/leaves/leave.aspx"
subfunction name="添加留言" url="~/page/leaves/leave.aspx"
/subfunction
subfunction name="修改留言" url="~/page/leaves/leave.aspx"
/subfunction
/function
/functions

2：后台代码

/// summary
/// 初始化功能树结构
/// /summary
private void InitFunction()
{
XmlDocument xmldoc = new XmlDocument();
string xmlPath = "~/adminFunction.xml";
xmlPath = Server.MapPath(xmlPath);
xmldoc.Load(xmlPath);
XmlNode root = xmldoc.DocumentElement;
tvFunction.Nodes.Add(CreateNode(root,new TreeNode()));
}
/// summary
/// 递归方法产生树（create by 轻狂书生）
/// /summary
/// param name="root" 根节点 /param
/// param name="tn" 根节点对应的树节点 /param
/// returns /returns
private TreeNode CreateNode(XmlNode root, TreeNode tn)
foreach (XmlNode node in root.ChildNodes)
{
XmlElement subxmlEmt = node as XmlElement;
string subname = subxmlEmt.GetAttribute("name");
string suburl = subxmlEmt.GetAttribute("url");
TreeNode subtn = new TreeNode();
subtn.Text = subname;
subtn.NavigateUrl = suburl;
if (node.HasChildNodes)
{
subtn.ChildNodes.Add(CreateNode(node,subtn));
}
tn.ChildNodes.Add(subtn);
}
return tn;
}

3：产生的效果图如下

4：为了去除根节点的显示，好像只能用个循环了，修改如下

/// summary
/// 初始化功能树结构
/// /summary
private void InitFunction()
{
XmlDocument xmldoc = new XmlDocument();
string xmlPath = "~/adminFunction.xml";
xmlPath = Server.MapPath(xmlPath);
xmldoc.Load(xmlPath);
XmlNode root = xmldoc.DocumentElement;
foreach (XmlNode node in root.ChildNodes)
{
XmlElement subxmlEmt = node as XmlElement;
string subname = subxmlEmt.GetAttribute("name");
string suburl = subxmlEmt.GetAttribute("url");
TreeNode subtn = new TreeNode();
subtn.Text = subname;
subtn.NavigateUrl = suburl;
tvFunction.Nodes.Add(CreateNode(node, subtn));
}
}

5：显示效果如下

达到了预期的效果哦，呵呵，请问方法有什么可以改进的么？请大神各抒己见..test类别