android–用于httppost的线程和Asynctask任务

朋友们,我需要帮助使用Asynctask或Threads将android httppost数据发送到服务器
当我点击发布按钮时,我需要将数据发送到我的服务器.但是当我点击它时,应用程序需要转到下一页,数据需要通过后台进程发送.我是Android新手.我不知道是什么正好用于这种任务(Threads或Asyanctask).
我试过这段代码,但它会给我异常错误

public void startProgress(final String name) {
// Do something long
Runnable runnable = new Runnable() {
@Override
public void run() {
try {
Thread.sleep(500);
send(name);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
};
new Thread(runnable).start();
}
public void send(String name)
{
// get the message from the message text box
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://10.0.2.2:8080/Test");
try {
List nameValuePairs = new ArrayList(2);
String co2 =input_field.getText().toString();
nameValuePairs.add(new BasicNameValuePair("Name", name));
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
Toast toast = Toast.makeText(getApplicationContext(), "Got it ", Toast.LENGTH_SHORT);
toast.show();
httpclient.execute(httppost);
input_field.setText("");
} catch(Exception e){
Toast toast2 = Toast.makeText(getApplicationContext(), "error", Toast.LENGTH_SHORT);
toast2.show();
}
}


但是,如果我这样使用它它的工作原理.(文本是该页面中的TextView项目)

public void startProgress(final String name) {
// Do something long
Runnable runnable = new Runnable() {
@Override
public void run() {
try {
Thread.sleep(500);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
text.post(new Runnable() {
@Override
public void run() {
send(name);
}
});
}
};
new Thread(runnable).start();
}


在下面的代码中你可以解释一下这个问题

text.post(new Runnable() {
@Override
public void run() {
send(name);
}
});


请帮我解决这个问题.如果有更好的方法来满足我的需求请提及它.因为它对Android开发的经验很少

解决方法:

您可以使用AsyncTask执行此操作,如下所示：

public class HttpPostExanple extends AsyncTask
{
@Override
protected String doInBackground(String... params)
{
BufferedReader inBuffer = null;
String url = "http://10.0.2.2:8080/Test";
String result = "fail";
try {
HttpClient httpClient = new DefaultHttpClient();
HttpPost request = new HttpPost(url);
List postParameters = new ArrayList();
postParameters.add(new BasicNameValuePair("name", params[0]));
UrlEncodedFormEntity formEntity = new UrlEncodedFormEntity(
postParameters);
request.setEntity(formEntity);
httpClient.execute(request);
result="got it";
} catch(Exception e) {
// Do something about exceptions
result = e.getMessage();
} finally {
if (inBuffer != null) {
try {
inBuffer.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
return result;
}
protected void onPostExecute(String page)
{
//textView.setText(page);
Toast toast = Toast.makeText(getApplicationContext(), page, Toast.LENGTH_SHORT);
toast.show();
}
}


你需要在主方法中使用它

new HttpPostExample().execute(new String[] {name});


看一下这个.
希望这会帮助你.