作者:Libra | 来源:互联网 | 2022-12-02 13:32
我有以下原型:
syntax = "proto3";
import "google/rpc/status.proto";
message Response {
google.rpc.Status status = 1;
}
message Request {
Type name = 1;
}
service Service {
rpc SomeMethod (Request) returns (Response);
}
我在节点中编写一个客户端:
const path = require('path');
const grpc = require('grpc');
const protoLoader = require('@grpc/proto-loader');
const protoFiles = require('google-proto-files');
const PROTO_PATH = path.join(__dirname, '/proto/myproto.proto');
const packageDefinition = protoLoader.loadSync(
PROTO_PATH,
{
keepCase: true,
longs: String,
enums: String,
defaults: true,
oneofs: true,
includeDirs: [protoFiles('rpc')],
},
);
const proto = grpc.loadPackageDefinition(packageDefinition);
const client = new proto.Service('localhost:1111', grpc.credentials.createInsecure());
运行客户端时,出现以下错误:TypeError:proto.Service不是构造函数。我发现它与status.proto的导入有关。使用proto-loader导入google proto的正确方法是什么?该服务器使用Java。
1> Maxim Sobole..:
奥尔加(Olga),如果您使用includeDirs,则不能在PROTO_PATH中使用绝对路径。显然,您需要将两个路径(即myproto.proto的路径和google-proto文件的路径)放入includeDirs中,并仅使用文件名作为PROTO_PATH,然后它就可以正常工作。看这里:
https://github.com/grpc/grpc-node/issues/470
这是有效的修改后的代码。请注意,我还必须在myproto.proto中将“ Type”替换为“ int32”。
const path = require('path');
const grpc = require('grpc');
const protoLoader = require('@grpc/proto-loader');
const protoFiles = require('google-proto-files');
const PROTO_PATH = 'myproto.proto';
const packageDefinition = protoLoader.loadSync(
PROTO_PATH,
{
keepCase: true,
longs: String,
enums: String,
defaults: true,
oneofs: true,
includeDirs: ['node_modules/google-proto-files', 'proto']
},
);
const protoDescriptor = grpc.loadPackageDefinition(packageDefinition);
const client = new protoDescriptor.Service('localhost:1111', grpc.credentials.createInsecure());
希望能帮助到你。:)