使用Django存储整数数组-StoringanarrayofintegerswithDjango

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The only difference between this field type and a CharField is that it validates that the data is in the proper format - only digits separated by ','. You can view the source for the class at http://docs.nullpobug.com/django/trunk/django.db.models.fields-pysrc.html#CommaSeparatedIntegerField (expand the '+').

此字段类型与CharField之间的唯一区别是它验证数据的格式是否正确 - 只有数字以','分隔。您可以在http://docs.nullpobug.com/django/trunk/django.db.models.fields-pysrc.html#CommaSeparatedIntegerField(展开'+')查看该类的源代码。

You can turn such a string into an actual Python list value (not array - list is the proper term for Python) by using eval.

您可以使用eval将这样的字符串转换为实际的Python列表值(不是数组 - 列表是Python的正确术语)。

>>> eval("[1,2,3,4]")
[1, 2, 3, 4]

EDIT: eval has safety concerns, however and a better method is to use literal_eval as suggest by Alvin in another answer.

编辑:eval有安全问题,但更好的方法是使用literal_eval作为Alvin在另一个答案中的建议。

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Eval was accepted as answer above -- avoid the temptation it's just not safe

Eval被接受作为上面的答案 - 避免诱惑它只是不安全

See: Python: make eval safe

请参阅:Python:使eval安全

There is a literal_eval function that could be used the same way:

有一个literal_eval函数可以使用相同的方式:

>>> from ast import literal_eval
>>> literal_eval("[1,2,3,4]")
[1, 2, 3, 4]