使用普通js传递AJAX请求的数组?-PassarrayonAJAXrequestusingplainjs?

2  

Use this:

用这个:

xmlhttp.send('myArray='+JSON.stringify(myArray));

At php side,

在php身边,

$array= json_decode($_POST['myArray']);

1  

The .send() method accepts a string which is the POST data to be sent in the request. In jQuery, the data property allows you to pass an object (which you have), but behind the scenes, jQuery converts the object into a key/value pairs format.

send()方法接受一个字符串，该字符串是在请求中发送的POST数据。在jQuery中，数据属性允许您传递一个对象(您有)，但是在幕后，jQuery将对象转换为键/值对格式。

This is the format that you must pass to .send() because it doesn't automatically convert objects into the key/value string.

这是必须传递给.send()的格式，因为它不会自动地将对象转换为键/值字符串。

For example, to send myArray with three elements:

例如，向myArray发送三个元素:

xmlhttp.setRequestHeader("Content-type", "application/x-www-form-urlencoded")
xmlhttp.send('myArray[]=first&myArray[]=second&myArray[]=third');

Remember to include the header, to tell the server side which format you are sending POST data in.

记住要包含报头，告诉服务器端要发送的是哪种格式的POST数据。

A function to convert a simple 1 dimensional array to this format could look like:

将一个简单的一维数组转换成这种格式的函数可以是:

function arrayToKeyValueString(name, arr){
    var str = name + '[]=';
    for(var i=0; i

xmlhttp.send('myArray=' + encodeURIComponent(JSON.stringify(myArray)));