如何在sqlserver中用new替换第二个位置字符串

我有一个问题:在sql server中,如何将第二次出现的字符串替换happy为字符串new,否则保持原样(相同).

表:

CREATE TABLE [dbo].[stringrep](
    [name] [varchar](100) NULL,
    [id] [int] NULL
) 
INSERT [dbo].[stringrep] ([name], [id]) VALUES (N'happy happy year', 1)
GO
INSERT [dbo].[stringrep] ([name], [id]) VALUES (N'very happy new year', 2)
GO
INSERT [dbo].[stringrep] ([name], [id]) VALUES (N'happy new year hello', 3)
GO
INSERT [dbo].[stringrep] ([name], [id]) VALUES (N'happy  happy year', 4)
GO
INSERT [dbo].[stringrep] ([name], [id]) VALUES (N'heloo year happy', 5)
GO
INSERT [dbo].[stringrep] ([name], [id]) VALUES (N'happy happy happy year', 6)
GO

基于以上数据,我想要输出如下:

  id  |        Name 
  1   | happy new year
  2   | very happy new year
  3   | happy new year hello
  4   | happy  new year
  5   | heloo year happy
  6   |happy new happy year

我尝试了以下查询:

SELECT replace ( name  ,'happy happy year' ,'happy new year')afterreplacename,
replace (  name, substring ('happy happy year'  ,6,6) ,' new')anotherway
,name ,[id]
  FROM [test].[dbo].[stringrep]

上述查询未给出预期结果.

请告诉我如何在sql server中完成此任务.