如何用符号修剪/剪切java中的字符串？-Howtotrim/cutstringinjavabysymbol?

At the moment I'm using java's string function called substring() but this not the best approach as IDs could become 3 digit numbers and I would only get part of it. Heres my current approach:

目前我正在使用java的字符串函数substring（），但这不是最好的方法，因为ID可能会成为3位数字，我只会得到它的一部分。继承了我目前的做法：

String id = advertiserUrl.substring(advertiserUrl.length()-1,advertiserUrl.length());
System.out.println(id) //4

It works in this case but if id would be e.g "123" I would only get it as "3" after using substring, so my question is: is there a way to cut/trim string using dashes "/"? lets say theres 5 / in my current url so the string would get cut off after it detects fifth dash? Also any other sensible approach would be helpful too. Thanks.

它适用于这种情况，但如果id为例如“123”，我只会在使用子字符串后得到它为“3”，所以我的问题是：有没有办法用破折号“/”剪切/修剪字符串？让我说当前网址中的theres 5 /所以字符串在检测到第五个破折号后会被切断？任何其他合理的方法也会有所帮助。谢谢。

P.s uuid in url may vary in length too

url中的P.suuid也可能在长度上有所不同

3 个解决方案

String advertiserUrl = "http://../../.../uuid/advertisers/4";// <<

4

String advertiserUrl = "http://111.111.11.111:1111/api/ppppp/2f5d1a31-878a-438b-a03b-e9f51076074a/adver‌​tisers/9";
//                           | preceded by "/"
//                           |     | any non-"/" character, reluctantly quantified
//                           |     |     | followed by "/advertisers"
Pattern p = Pattern.compile("(?<=/)[^/]+?(?=/adver‌​tisers)");
Matcher m = p.matcher(advertiserUrl);
if (m.find()) {
    System.out.println(m.group());
}

String id = advertiserUrl.substring(advertiserUrl.lastIndexOf('/') + 1, advertiserUrl.length());