如何将Python分割为一个角色但仍保留该角色？-HowtoPythonsplitbyacharacteryetmaintainthatcharacter?

7  

Don't use regex. Just split the string on the '\n'. The last index is a phone number, the other indexes are the address.

不要使用正则表达式。只需将字符串拆分为'\ n'即可。最后一个索引是电话号码,其他索引是地址。

lines   = inputString.split('\n')
phOne= lines[-1] if lines[-1].match(REGEX_PHONE_US) else None
address = '\n'.join(lines[:-1]) if phone else inputString

Python has a lot of great built in tools for manipulating strings in a more... human way... than regex allows.

Python有很多很棒的内置工具,用于以更人性化的方式操作字符串......而不是正则表达式允许的。

1  

If I understand you correctly, you want to "extract the first X lines as address". Assuming that all the addresses you need are in the US this regex code should work for you. In any case, it works on the 3 examples you provided:

如果我理解正确,你想“将前X行提取为地址”。假设您需要的所有地址都在美国,这个正则表达式代码应该适合您。无论如何,它适用于您提供的3个示例:

import re
x = 'Wildwood, MO\nUnited States\n(636) 458-7707'
print re.findall(r'.*\n+.*\States', x)

The output is:

输出是:

['Wildwood, MO\nUnited States']

If you want to print it later without the \n you can do it this way:

如果你想在没有\ n的情况下打印它,你可以这样做:

x = '\n113 W 5th St\nEureka, MO, United States\n(636) 938-9310\n'
y = re.findall(r'.*\n+.*\States', x)
y = y[0].rstrip()

When you print y the output:

当您打印输出时:

113 W 5th St
Eureka, MO, United States

And, if you want to extract the phone number separately you can do this:

而且,如果您想单独提取电话号码,您可以这样做:

tel = '\n113 W 5th St\nEureka, MO, United States\n(636) 938-9310\n'
num = re.findall(r'.*\d+\-\d+', tel)
num = num[0].rstrip()

When you print num the output:

当你打印num输出时:

(636) 938-9310