本文是 2021年春季学期-信号与系统-第十三次作业参考答案 中各小题答案。
§11 第十一小题
12. 已知下列系统,用几何作图法粗略画出它们的幅频和相频特性。
(1)
H
(
z
)
=
2
z
z
−
0.6
H\\left( z \\right) = {{2z} \\over {z - 0.6}}\\;\\;\\;\\;\\;
H(z)=z−0.62z(2)
H
(
z
)
=
(
0.96
+
z
−
1
)
2
0.36
z
−
2
+
1
H\\left( z \\right) = {{\\left( {0.96 + z^{ - 1} } \\right)^2 } \\over {0.36z^{ - 2} + 1}}\\;\\;\\;\\;\\;
H(z)=0.36z−2+1(0.96+z−1)2
▓ 求解:
(1)第一小题
H
(
z
)
=
2
z
z
−
0.6
H\\left( z \\right) = {{2z} \\over {z - 0.6}}\\;\\;\\;\\;\\;
H(z)=z−0.62z
(2)第二小题
H
(
z
)
=
(
0.96
+
z
−
1
)
2
0.36
z
−
2
+
1
H\\left( z \\right) = {{\\left( {0.96 + z^{ - 1} } \\right)^2 } \\over {0.36z^{ - 2} + 1}}\\;\\;\\;\\;\\;
H(z)=0.36z−2+1(0.96+z−1)2
MATLAB命令:
syms z;
theta=linspace(0,2*pi,100);
h=inline(2*z/(z-0.6));
plot(abs(h(exp(i*theta)));
plot(angle(h(exp(i*theta)));
(1)第一小题
>>h=tf([2,0],[1,-0.6],1,'variable','z')'
2z
h= -------
z-0.6
Sampletime:1 seconds,Discrete-timetransferfunction
pzmap(h)
(2)第二小题
>>h=tf([0.96*0.96,2*0.96,1],[1,0,0.36],1,'variable','z^-1')'
0.9216+1.92z^-1+z^-2
h=-------------------------
1+0.36z^-2
Sampletime:1 seconds,Discrete-timetransferfunction.
pzmap(h)
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