作者:杰v杰123_246 | 来源:互联网 | 2022-12-03 11:40
我正在使用SwiftType Elastic Search + C#并遇到反序列化响应的问题,原因是SwiftType将所有字段作为具有raw
属性的对象返回为对象(https://swiftype.com/documentation/app-search/api / search),例如:
{
"meta": {
"warnings": [],
"page": {
"current": 1,
"total_pages": 1,
"total_results": 2,
"size": 10
},
"request_id": "6887a53f701a59574a0f3a7012e01aa8"
},
"results": [
{
"phone": {
"raw": 3148304280.0
},
"accounts_balance_ach": {
"raw": 27068128.71
},
"accounts_balance_pending": {
"raw": "46809195.64"
},
"email": {
"raw": "Brisa34@hotmail.com"
},
"accounts_count": {
"raw": 6.0
},
"id": {
"raw": "c98808a2-d7d6-4444-834d-2fe4f6858f6b"
},
"display_name": {
"raw": "The Johnstons"
},
"type": {
"raw": "Couple"
},
"advisor_email": {
"raw": "Cornelius_Schiller14@hotmail.com"
},
"created_at": {
"raw": "2018-10-02T10:42:07+00:00"
},
"source": {
"raw": "event"
},
"accounts_balance": {
"raw": 43629003.47
},
"accounts_donations": {
"raw": 38012278.75
},
"advisor_name": {
"raw": "Cloyd Jakubowski"
},
"_meta": {
"score": 0.42934617
}
},
{
"phone": {
"raw": 2272918612.0
},
"accounts_balance_ach": {
"raw": 35721452.35
},
"accounts_balance_pending": {
"raw": "35117465.2"
},
"email": {
"raw": "Ruby87@yahoo.com"
},
"accounts_count": {
"raw": 1.0
},
"id": {
"raw": "687af11f-0f73-4112-879c-1108303cb07a"
},
"display_name": {
"raw": "Kennith Johnston"
},
"type": {
"raw": "Individual"
},
"advisor_email": {
"raw": "Evangeline_Wisoky92@hotmail.com"
},
"created_at": {
"raw": "2018-10-02T16:16:02+00:00"
},
"source": {
"raw": "website"
},
"accounts_balance": {
"raw": 23063874.19
},
"accounts_donations": {
"raw": 33025175.79
},
"advisor_name": {
"raw": "Ernie Mertz"
},
"_meta": {
"score": 0.39096162
}
}
]
}
我需要将每个键映射到其值,例如results [0] .email =“ Brisa34@hotmail.com”;
我看到了自定义转换器的一个有前途的选项,但是我想确保在采用详细方法之前没有更动态的方法来执行此操作。
1> Brian Rogers..:
我建议使用可以在属性中指定路径以将JsonPathConverter
类中的属性映射到JSON中的子属性的类吗?。这将允许您声明一个强类型的Result
类,然后轻松地将每个属性映射到raw
JSON中相应子值的值,而不必声明大量笨拙的单属性类。
如下所示声明您的模型。请注意,Result
该类需要[JsonConverter]
在其上绑定一个属性JsonPathConverter
(否则,属性路径将不起作用,并且您将在属性中获得默认值)。
public class RootObject
{
public List results { get; set; }
}
[JsonConverter(typeof(JsonPathConverter))]
public class Result
{
[JsonProperty("phone.raw")]
public string Phone { get; set; }
[JsonProperty("accounts_balance_ach.raw")]
public decimal AccountsBalanceAch { get; set; }
[JsonProperty("accounts_balance_pending.raw")]
public decimal AccountsBalancePending { get; set; }
[JsonProperty("email.raw")]
public string Email { get; set; }
[JsonProperty("accounts_count.raw")]
public decimal AccountsCount { get; set; }
[JsonProperty("id.raw")]
public string Id { get; set; }
[JsonProperty("display_name.raw")]
public string DisplayName { get; set; }
[JsonProperty("type.raw")]
public string Type { get; set; }
[JsonProperty("advisor_email.raw")]
public string AdvisorEmail { get; set; }
[JsonProperty("created_at.raw")]
public string CreatedAt { get; set; }
[JsonProperty("source.raw")]
public string Source { get; set; }
[JsonProperty("accounts_balance.raw")]
public decimal AccountsBalance { get; set; }
[JsonProperty("accounts_donations.raw")]
public decimal AccountsDonations { get; set; }
[JsonProperty("advisor_name.raw")]
public string AdvisorName { get; set; }
[JsonProperty("_meta.score")]
public decimal MetaScore { get; set; }
}
然后,您可以照常反序列化:
var root = JsonConvert.DeserializeObject(json);
这是一个有效的演示:https : //dotnetfiddle.net/wYxwIF