获取目录中的文件夹列表-Gettingalistoffoldersinadirectory

62  

Jordan is close, but Dir.entries doesn't return the full path that File.directory? expects. Try this:

乔丹很接近，但是迪尔。条目没有返回File.directory的完整路径?预计。试试这个:

 Dir.entries('/your_dir').select {|entry| File.directory? File.join('/your_dir',entry) and !(entry =='.' || entry == '..') }

90  

I've found this more useful and easy to use:

我发现这个更有用，更容易使用:

Dir.chdir('/destination_directory')
Dir.glob('*').select {|f| File.directory? f}

it gets all folders in the current directory, excluded . and ...

它获取当前目录中的所有文件夹，排除。和…

To recurse folders simply use ** in place of *.

要递归文件夹，只需使用**代替*。

The Dir.glob line can also be passed to Dir.chdir as a block:

Dir。glob行也可以传递给Dir。作为一个整体是指:

Dir.chdir('/destination directory') do
  Dir.glob('*').select { |f| File.directory? f }
end

40  

In my opinion Pathname is much better suited for filenames than plain strings.

在我看来，路径名比纯字符串更适合文件名。

require "pathname"
Pathname.new(directory_name).children.select { |c| c.directory? }

This gives you an array of all directories in that directory as Pathname objects.

这将为您提供该目录中作为路径名对象的所有目录的数组。

If you want to have strings

如果你想要字符串

Pathname.new(directory_name).children.select { |c| c.directory? }.collect { |p| p.to_s }

If directory_name was absolute, these strings are absolute too.

如果directory_name是绝对的，那么这些字符串也是绝对的。

18  

Recursively find all folders under a certain directory:

递归查找某个目录下的所有文件夹:

Dir.glob 'certain_directory/**/*/'

Non-recursively version:

非递归版本:

Dir.glob 'certain_directory/*/'

Note: Dir.[] works like Dir.glob.

注意:Dir。[]Dir.glob等工作。

4  

You can use File.directory? from the FileTest module to find out if a file is a directory. Combining this with Dir.entries makes for a nice one(ish)-liner:

您可以使用File.directory吗?从FileTest模块查找文件是否为目录。结合Dir。条目是一个不错的(有点)-内衬:

directory = 'some_dir'
Dir.entries(directory).select { |file| File.directory? File.join(directory, file}

Edit: Updated per ScottD's correction.

编辑:根据ScottD的更正更新。

4  

directory = 'Folder'
puts Dir.entries(directory).select { |file| File.directory? File.join(directory, file)}

1  

Dir.glob('/your_dir').reject {|e| !File.directory?(e)}

1  

$dir_target = "/Users/david/Movies/Camtasia 2/AzureMobileServices.cmproj/media"

Dir.glob("#{$dir_target}/**/*").each do |f| 
  if File.directory?(f)
    puts "#{f}\n"
  end
end

0  

I think you can test each file to see if it is a directory with FileTest.directory? (file_name). See the documentation for FileTest for more info.

我认为您可以测试每个文件，看看它是否是带有FileTest.directory的目录?(file_name)。更多信息请参见文件测试文档。

0  

For a generic solution you probably want to use

对于您可能想要使用的通用解决方案

Dir.glob(File.expand_path(path))

This will work with paths like ~/*/ (all folders within your home directory).

这将与~/*/(主目录中的所有文件夹)之类的路径一起工作。

0  

We can combine Borh's answer and johannes' answer to get quite an elegant solution to getting the directory names in a folder.

我们可以把Borh的答案和johannes的答案结合起来，得到一个很好的解决方案，让目录名在一个文件夹中。

# user globbing to get a list of directories for a path
base_dir_path = ''
directory_paths = Dir.glob(File.join(base_dir_path, '*', ''))

# or recursive version:
directory_paths = Dir.glob(File.join(base_dir_path, '**', '*', ''))

# cast to Pathname
directories = directory_paths.collect {|path| Pathname.new(path) }

# return the basename of the directories
directory_names = directories.collect {|dir| dir.basename.to_s }

0  

Only folders ('.' and '..' are excluded):

只有文件夹(”。’和‘. .的除外):

Dir.glob(File.join(path, "*", File::SEPARATOR))

Dir.glob(文件。加入(文件路径、“*”:分隔符))

Folders and files:

文件夹和文件:

Dir.glob(File.join(path, "*"))

Dir.glob(文件。加入(路径,“*”))