作者:双木子婷_893 | 来源:互联网 | 2023-05-28 14:21
我有一个属性文件,我想在服务中注入一个属性.
我想像这样使用DI的构造函数方法:
@Inject
public ScanService(@Named("stocks.codes") String codes, IYahooService yahooService) {
this.yahooService = yahooService;
this.codes = codes;
}
我尝试做一个像这个链接中指定的模块=> Dagger:注入@Named字符串?
@Provides
@Named("stocks.code")
public String providesStocksCode() {
return "test";
}
对于我的服务的提供者方法:
@Provides
@Singleton
public IScanService provideScanService(String codes, IYahooService yahooService){
return new ScanService(codes, yahooService);
}
当我运行编译时,我收到此错误:
[ERROR] /Users/stocks/src/main/java/net/modules/TestModule.java:[22,7]错误:上java.lang.String中未注射的成员.你想添加一个注射构造函数吗?通过provideScanService(java.lang.String中,net.IYahooService),用于net.modules.TestModule所需
如何在构造函数中正确注入我的属性?
谢谢.
1> voronnenok..:
如果你的意思是Dagger 2,我可以帮助你.首先,您必须在Component中声明依赖项
@Singleton
@Component(modules = ApplicationModule.class)
public interface ApplicationComponent {
void inject(BaseActivity baseActivity);
@Named("cloud") UserDataSource userCloudSource();
@Named("disc") UserDataSource userDiscSource();
UserDataRepository userDataRepository();
}
然后在Module中实例化它
@Module
public class ApplicationModule {
@Provides @Named("cloud")
UserDataSource provideCloudUserSource(UserCloudSource userSource) {
return userSource;
}
@Provides @Named("disc")
UserDataSource provideDiscUserSource(UserDiscSource userSource) {
return userSource;
}
@Provides
UserDataRepository provideUserRepository(UserDataRepository repository) {
return repository;
}
}
然后使用@Named限定符在构造函数中注入它
@Inject
public UserDataRepository(@Named("cloud") UserDataSource cloudSource,
@Named("disc") UserDataSource discSource) {
this.cloudDataSource= cloudSource;
this.discDataSource = discSource;
}
2> nhaarman..:
你有两个不同的名字:stocks.codes
和stocks.code
.
您还必须注释您的provideScanService
codes
参数:
@Provides
@Singleton
public IScanService provideScanService(@Named("stocks.codes") String codes, IYahooService yahooService){
return new ScanService(codes, yahooService);
}
或者这样做:
@Provides
@Singleton
public IScanService provideScanService(ScanService scanService){
return scanService;
}