作者:chenshuping9338 | 来源:互联网 | 2022-12-07 16:52
我需要\"
从矢量中删除.这是我的数据:
data <- c("\"https://click.linksynergy.com/link?id=RUxZriH*PWc&offerid=323058.1803224&type=2&murl=https%3A%2F%2Fwww.udemy.com%2Flinux-linux-security-masterclass-3-in-1%2F",
"\"https://click.linksynergy.com/link?id=RUxZriH*PWc&offerid=323058.1848638&type=2&murl=https%3A%2F%2Fwww.udemy.com%2Fmastering-kali-linux%2F",
"\"https://click.linksynergy.com/link?id=RUxZriH*PWc&offerid=323058.1426684&type=2&murl=https%3A%2F%2Fwww.udemy.com%2Finformation-gathering-with-kali-linux%2F",
"\"https://click.linksynergy.com/link?id=RUxZriH*PWc&offerid=323058.1628300&type=2&murl=https%3A%2F%2Fwww.udemy.com%2Flinux-switchblade%2F",
"\"https://click.linksynergy.com/link?id=RUxZriH*PWc&offerid=323058.1615700&type=2&murl=https%3A%2F%2Fwww.udemy.com%2Fadministrador-de-sistemas-junior-en-windows-server-y-linux%2F",
"\"https://click.linksynergy.com/link?id=RUxZriH*PWc&offerid=323058.809770&type=2&murl=https%3A%2F%2Fwww.udemy.com%2Flearn-bash-shell-in-linux-for-beginners-lite%2F",
"\"https://click.linksynergy.com/link?id=RUxZriH*PWc&offerid=323058.574388&type=2&murl=https%3A%2F%2Fwww.udemy.com%2Fhow-to-install-linux-ubuntu-server%2F",
"\"https://click.linksynergy.com/link?id=RUxZriH*PWc&offerid=323058.1436610&type=2&murl=https%3A%2F%2Fwww.udemy.com%2Fcentos-and-ubuntu-managing-packages%2F",
"\"https://click.linksynergy.com/link?id=RUxZriH*PWc&offerid=323058.1771266&type=2&murl=https%3A%2F%2Fwww.udemy.com%2Flinux-foundation-certified-system-administrator-exam%2F",
"\"https://click.linksynergy.com/link?id=RUxZriH*PWc&offerid=323058.1734052&type=2&murl=https%3A%2F%2Fwww.udemy.com%2Flinux-server-security%2F"
)
如您所见,每个对象都以\"
.我怎样才能专门删除这些字符并留下链接?
1> milan..:
你可以试试这个.请注意,您真正想要的是删除\"
,而不是"\
(根据您的问题的未经编辑的版本中提出).首先"
需要表示角色中的每个元素.
gsub('[\"]', '', data)
2> akrun..:
或者我们可以只'"'
在模式上使用
gsub('"', "", data)
3> zx8754..:
如果它始终是第一个字符,那么只需使用子字符串:
substring(data, 2)
这应该比任何正则表达式解决方案更快.
data <- rep(data, 1000)
microbenchmark::microbenchmark(
a = substring(data, 2),
b = gsub("\"", "", data, fixed = TRUE),
c = gsub('"', "", data),
d = gsub('[\"]', '', data),
e = stringr::str_replace(data, '[\"]', ''),
f = gsub("^.","",data)
)
# Unit: milliseconds
# expr min lq mean median uq max neval
# a 2.835013 2.849838 2.933796 2.857393 2.900301 4.446956 100
# b 4.728632 4.739751 4.788882 4.754861 4.795203 5.200185 100
# c 7.388025 7.413684 7.503427 7.458444 7.555520 8.160925 100
# d 7.390876 7.412686 7.530044 7.454453 7.533568 8.535544 100
# e 12.019154 12.205608 12.430870 12.316084 12.581081 13.917336 100
# f 15.712882 15.735975 15.875353 15.770043 15.861275 18.906262 100