查找并删除Javascript对象数组中的第一个匹配元素

假设我有一个数组:

    members = [
        {name: 'Anna', class: 'one'}, 
        {name: 'Bob', class: 'two'},  
        {name: 'Chuck', class: 'two'}];

    removed = members.myRemoveByClass('two');     //something like

    // removed is {name: 'Bob', class: 'two'} 
    // members is [{name: 'Anna', class: 'one'}, {name: 'Chuck', class: 'two'}]

我正在寻找一些东西myRemoveByClass.ES2015很好或使用Lodash.该阵列已经订购.无的问题,我已经看到相当符合我正在寻找的.

您可以创建自己的Array类:

 class Members extends Array {
   removeByClass(className) {
     for(const [index, member] of this.entries())
        if(member.class === className) 
           return this.splice(index, 1)[0];
   }
}

用它作为

 const members = new Members([ {/*...*/}, {/*...*/} ]);
 members.removeByClass("...");

PS:"class"是一个非常糟糕的名字,因为它是一个保留的关键字

您可以使用Array.prototype.findIndex（）：

该findIndex()方法返回满足提供的测试功能的数组中第一个元素的索引。否则，它返回-1，表示没有元素通过测试。

var members = [
        {name: 'Anna', class: 'one'}, 
        {name: 'Bob', class: 'two'},  
        {name: 'Chuck', class: 'two'}];
var idx = members.findIndex(p => p.class=="two");
var removed = members.splice(idx,1);     
console.log(removed);
console.log(members);