phonegap pushwoosh插件registerDevice回调函数永远不会在android上激活

我正在尝试使用Pushwoosh推送通知phonegap构建插件,但registerDevice回调永远不会在我的Android设备上触发,但initPushwoosh功能会触发,因为我在下面的代码中看到来自警报("initPushwoosh")的警报

下面是我的config.xml

    Push notification

    
        Camera example app.
    

    
        PhoneGap Team
    

     

    

     

     

这是我的index.js,我只是将项目ID和appid更改为XXXX,这样我就不会错误地透露太多.

var app = {
    // Application Constructor
    initialize: function() {
        this.bindEvents();
    },
    // Bind Event Listeners
    //
    // Bind any events that are required on startup. Common events are:
    // 'load', 'deviceready', 'offline', and 'online'.
    bindEvents: function() {
        document.addEventListener('deviceready', this.onDeviceReady, false);
    },
    // deviceready Event Handler
    //
    // The scope of 'this' is the event. In order to call the 'receivedEvent'
    // function, we must explicity call 'app.receivedEvent(...);'
    onDeviceReady: function() {
        alert("onDeviceReady" );
        app.initPushwoosh();
        app.receivedEvent('deviceready');

    },

    initPushwoosh: function() {
        alert("initPushwoosh" );
            var pushNotification = window.plugins.pushNotification;
            pushNotification.registerDevice(
            { projectid: "XXX-XXX-XXXX 3", appid : "XXXXX-XXXXX" },
                function(status) {
                    var pushToken = status;
                    alert('push token: ' + pushToken);
                },
                function(status) {
                    alert(JSON.stringify(['failed to register ', status]));
            });
            document.addEventListener('push-notification', function(event) {            
                var title = event.notification.title;
                 var userData = event.notification.userdata;
                if (typeof(userData) != "undefined") {
                   alert('user data: ' + JSON.stringify(userData));
                }    
                navigator.notification.alert(title);
            });
    },
    // Update DOM on a Received Event
    receivedEvent: function(id) {
        var parentElement = document.getElementById(id);
        var listeningElement = parentElement.querySelector('.listening');
        var receivedElement = parentElement.querySelector('.received');

        listeningElement.setAttribute('style', 'display:none;');
        receivedElement.setAttribute('style', 'display:block;');

        console.log('Received Event: ' + id);
    },

    takePicture: function() {
      navigator.camera.getPicture( function( imageURI ) {
        alert( imageURI );
      },
      function( message ) {
        alert( message );
      },
      {
        quality: 50,
        destinationType: Camera.DestinationType.FILE_URI
      });
    }
};

任何帮助将不胜感激...谢谢!