问

oracle db中具有多个字段的条件唯一约束

HenryJuliju 发布于 2023-02-03 12:08

我有这张桌子:

XPTO_TABLE (id, obj_x, date_x, type_x, status_x)

我想创建适用于领域的唯一约束(obj_x, date_x, type_x),只有当status_x <> 5.

我试图创建这个,但Oracle说:

line 1: ORA-00907: missing right parenthesis

CREATE UNIQUE INDEX UN_OBJ_DT_TYPE_STATUS
ON XPTO_TABLE(
    (CASE
         WHEN STATUS_X <> 5
         THEN
             (OBJ_X,
              TO_CHAR (DATE_X, 'dd/MM/yyyy'),
              TYPE_X)
         ELSE
             NULL
     END));

什么是正确的语法？

2 个回答

@jamesfrj:看起来你正在努力确保你的表只包含一个记录status <>5.

您可以尝试通过连接列来创建唯一的功能索引,如下所示

      create table XPTO_TABLE (id number, 
                            obj_x varchar2(20),
                            date_x date,
                            type_x varchar2(20),
                            status_x varchar2(20)                              
                           );

      create unique index xpto_table_idx1 on XPTO_TABLE(case when status_x <>'5'  THEN              obj_x||date_x||type_x||STATUS_x ELSE null END);

希望能帮助到你

Vishad

2023-02-03 12:09 回答

George_唐晓龙

在Oracle 11下,您可以创建一组虚拟列,仅当STATUS_X为5时才获取非NULL值,然后使它们唯一:

CREATE TABLE XPTO_TABLE (
  ID INT PRIMARY KEY,
  OBJ_X INT,
  DATE_X DATE,
  TYPE_X VARCHAR2(50),
  STATUS_X INT,
  OBJ_U AS (CASE STATUS_X WHEN 5 THEN OBJ_X ELSE NULL END),
  DATE_U AS (CASE STATUS_X WHEN 5 THEN DATE_X ELSE NULL END),
  TYPE_U AS (CASE STATUS_X WHEN 5 THEN TYPE_X ELSE NULL END),
  UNIQUE (OBJ_U, DATE_U, TYPE_U)
);

只要STATUS_X 不是 5 ,您就可以自由插入重复项:

INSERT INTO XPTO_TABLE (ID, OBJ_X, DATE_X, TYPE_X, STATUS_X) VALUES (1, 1, '1-JAN-2014', 'foo', 4);
INSERT INTO XPTO_TABLE (ID, OBJ_X, DATE_X, TYPE_X, STATUS_X) VALUES (2, 1, '1-JAN-2014', 'foo', 4);

但是当STATUS_X为5时尝试插入副本失败:

INSERT INTO XPTO_TABLE (ID, OBJ_X, DATE_X, TYPE_X, STATUS_X) VALUES (3, 1, '1-JAN-2014', 'foo', 5);
INSERT INTO XPTO_TABLE (ID, OBJ_X, DATE_X, TYPE_X, STATUS_X) VALUES (4, 1, '1-JAN-2014', 'foo', 5);

Error report -
SQL Error: ORA-00001: unique constraint (IFSAPP.SYS_C00139498) violated
00001. 00000 -  "unique constraint (%s.%s) violated"
*Cause:    An UPDATE or INSERT statement attempted to insert a duplicate key.
           For Trusted Oracle configured in DBMS MAC mode, you may see
           this message if a duplicate entry exists at a different level.
*Action:   Either remove the unique restriction or do not insert the key.

2023-02-03 12:10 回答

perfect_rl

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