objective-c - iOS开发，如何跳转到系统设置页？iOS10

针对iOS10不跳转问题，其实iOS提供了一套未公开方法。但审核是一个问题，不过我们可以想办法绕过审核。

NSString * defaultWork = [self getDefaultWork];
NSString * bluetoothMethod = [self getBluetoothMethod];
NSURL*url=[NSURL URLWithString:@"Prefs:root=Bluetooth"];
Class LSApplicationWorkspace = NSClassFromString(@"LSApplicationWorkspace");
[[LSApplicationWorkspace performSelector:NSSelectorFromString(defaultWork)] performSelector:NSSelectorFromString(bluetoothMethod) withObject:url withObject:nil];
利用ASCII值进行拼装组合方法。这样可绕过审核。

-(NSString *) getDefaultWork{
SData *dataOne = [NSData dataWithBytes:(unsigned char []) {0x64,0x65,0x66,0x61,0x75,0x6c,0x74,0x57,0x6f,0x72,0x6b,0x73,0x70,0x61,0x63,0x65} length:16];
NSString *method = [[NSString alloc] initWithData:dataOne encoding:NSASCIIStringEncoding];
return method;
}
-(NSString *) getBluetoothMethod{
NSData *dataOne = [NSData dataWithBytes:(unsigned char []){0x6f, 0x70, 0x65, 0x6e, 0x53, 0x65, 0x6e, 0x73, 0x69,0x74, 0x69,0x76,0x65,0x55,0x52,0x4c} length:16];
NSString *keyone = [[NSString alloc] initWithData:dataOne encoding:NSASCIIStringEncoding];
NSData *dataTwo = [NSData dataWithBytes:(unsigned char []){0x77,0x69,0x74,0x68,0x4f,0x70,0x74,0x69,0x6f,0x6e,0x73} length:11];
NSString *keytwo = [[NSString alloc] initWithData:dataTwo encoding:NSASCIIStringEncoding];
NSString *method = [NSString stringWithFormat:@"%@%@%@%@",keyone,@":",keytwo,@":"];
return method;
}
上面是进入蓝牙界面的方法。也可以有其他的页面可以跳转。设置页面是@"@"Prefs:root=TETHERING",wifi是@"Prefs:root=WIFI"。注意Prefs的P是大写。这么写也有弊端，如果苹果的未公开方法一旦修改。我们必须重新进行修改。

参考我的另外一个回答：https://segmentfault.com/q/10...

在ios10中跳转到具体的比如wifi，位置开关等具体的设置界面都已经被列为私有的API了，不允许使用；ios10只能跳转到相应的APP设置界面：
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:UIApplicationOpenSettingsURLString]];

把prefs: 换成Prefs: 就可以了

iOS10的URL换掉了，具体参照 https://github.com/cyanzhong/...
不过这个只在Widge里有效，App中无效。
用其他办法也可以做到跳转，不过因为是私有API会通不过审核。

参考：http://stackoverflow.com/ques...