问

java - Okhttp中如何在拦截器中的RequestBody添加参数？

王永星2012 发布于 2022-10-30 06:14

post

我想在所有POST请求中统一添加参数Token.(注意，不是添加在header里面)
如代码：我就是想把formBody2，添加在formBody中。

httpClient.addInterceptor(new Interceptor() {
            @Override
            public Response intercept(Chain chain) throws IOException {
                Request original = chain.request();

                FormBody formBody = (FormBody) original.body();

                FormBody formBody2 = new FormBody.Builder().add("token", “123456”).build();

                //请求定制：添加请求头
                Request.Builder requestBuilder = original.newBuilder()
                        .addHeader("APIKEY", Constant.API_KEY)
                        .method(original.method(),original.body());

                Request request = requestBuilder.build();
                return chain.proceed(request);
            }
        });

求帮助，谢了。

1 个回答

可以遍历formBody，循环添加 formBody
最好的办法是重写 FormBody，追加添加参数的方法。

OkHttpClient.Builder httpClient = new OkHttpClient.Builder()
httpClient.addInterceptor(new Interceptor() {
            @Override
            public Response intercept(Chain chain) throws IOException {
                Request original = chain.request();

                //请求定制：添加请求头
                Request.Builder requestBuilder = original.newBuilder()
                        .header("APIKEY", Constant.API_KEY);

                //请求体定制：统一添加token参数
                if(original.body() instanceof FormBody){
                    FormBody.Builder newFormBody = new FormBody.Builder();
                    FormBody oidFormBody = (FormBody) original.body();
                    for (int i = 0;i<oidFormBody.size();i++){
                        newFormBody.addEncoded(oidFormBody.encodedName(i),oidFormBody.encodedValue(i));
                    }
                    newFormBody.add("token",Constant.API_TOKEN);
                    requestBuilder.method(original.method(),newFormBody.build());
                }

                Request request = requestBuilder.build();
                return chain.proceed(request);
            }
        });

2022-11-12 01:48 回答

杨艳奎_718

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