http - java服务器获取远端ip地址

 平凡瞬间15 发布于 2022-11-04 07:06
public String getIpAddr(HttpServletRequest request) {  

    String ip = request.getHeader("x-forwarded-for");  
    if(ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {  
        ip = request.getHeader("Proxy-Client-IP");  
    }  
    if(ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {  
        ip = request.getHeader("WL-Proxy-Client-IP");  
    }  
    if(ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {  
        ip = request.getRemoteAddr();  
    }  
    System.out.println("本次登录的用户IP地址:"+ ip);
    return ip;
}

这里面的参数request在play!里面怎么传进去,或者play!有它本身获得ip地址的api吗?

1 个回答
  • Play Framework 中没有 HttpServletRequest,也不需要

    你的代码 可以改成

    public String getIpAddr() {  
    
        Request req = request();
        String ip = req.getHeader("x-forwarded-for");  
        if(ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {  
            ip = req.getHeader("proxy-client-ip");  
        }  
        if(ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {  
            ip = req.getHeader("wl-proxy-client-ip");  
        }  
        if(ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {  
            ip = req.remoteAddress();  
        }  
        System.out.println("本次登录的用户IP地址:"+ ip);
        return ip;
    }
    
    2022-11-07 10:43 回答
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