这是根据规范的Java双解析行为吗？

该java.lang.Double.parseValue方法以不一致的方式处理奇怪的双打表示.

如果你写了一个非常大的数字,那么它超出了double范围,但是然后附加一个大的负指数使它回到范围内,你最终在范围内(这里用Scala的REPL说明):

scala>
java.lang.Double.parseDouble("10000000000000000000000000000000000000000000
00000000000000000000000000000000000000000000000000000000000000000000000000
00000000000000000000000000000000000000000000000000000000000000000000000000
00000000000000000000000000000000000000000000000000000000000000000000000000
00000000000000000000000000000000000000000000000000000000000000000000000000
0000000000000000000000000000000000000001e-400")
res25: Double = 1.0E-21

另一方面,如果你写一个非常小的数字,这么小,它超出了double范围,但是然后使用一个大的正指数将它带回范围内,它只有在指数本身不是太大时才有效:

scala> 
java.lang.Double.parseDouble("0.000000000000000000000000000000000000000000
00000000000000000000000000000000000000000000000000000000000000000000000000
00000000000000000000000000000000000000000000000000000000000000000000000000
00000000000000000000000000000000000000000000000000000000000000000000000000
00000000000000000000000000000000000000000000000000000000000000000000000000
00000000000000000000000000000000000000001e400")
res26: Double = Infinity

scala>
java.lang.Double.parseDouble("0.000000000000000000000000000000000000000000
00000000000000000000000000000000000000000000000000000000000000000000000000
00000000000000000000000000000000000000000000000000000000000000000000000000
00000000000000000000000000000000000000000000000000000000000000000000000000
00000000000000000000000000000000000000000000000000000000000000000000000000
00000000000000000000000000000000000000001e200")
res27: Double = 1.0E-179

这只是一个错误,或者某个地方是否存在允许这种行为的规范,或者规范允许所有这些都失败了,当得到正确的结果时,应该感谢一个人的祝福？(如果它是一个错误,它已被修复？)

(旁白:我正在编写自定义的字符串到双重代码,并且会针对棘手案例推迟Java默认实现,但此测试用例失败.)