眼镜蛇指挥官如何去(golang)工作？

我想了解如何创建服装命令为旅途中使用的眼镜蛇(和蝮蛇)库,并能够使用它们.

具体而言,我试图理解并提供他们提供工作的例子.示例如下:

import(
    "github.com/spf13/cobra"
    "fmt"
    "strings"
)

func main() {

    var echoTimes int

    var cmdPrint = &cobra.Command{
        Use:   "print [string to print]",
        Short: "Print anything to the screen",
        Long:  `print is for printing anything back to the screen.
        For many years people have printed back to the screen.
        `,
        Run: func(cmd *cobra.Command, args []string) {
            fmt.Println("Print: " + strings.Join(args, " "))
        },
    }

    var cmdEcho = &cobra.Command{
        Use:   "echo [string to echo]",
        Short: "Echo anything to the screen",
        Long:  `echo is for echoing anything back.
        Echo works a lot like print, except it has a child command.
        `,
        Run: func(cmd *cobra.Command, args []string) {
            fmt.Println("Print: " + strings.Join(args, " "))
        },
    }

    var cmdTimes = &cobra.Command{
        Use:   "times [# times] [string to echo]",
        Short: "Echo anything to the screen more times",
        Long:  `echo things multiple times back to the user by providing
        a count and a string.`,
        Run: func(cmd *cobra.Command, args []string) {
            for i:=0; i < echoTimes; i++ {
                fmt.Println("Echo: " + strings.Join(args, " "))
            }
        },
    }

    cmdTimes.Flags().IntVarP(&echoTimes, "times", "t", 1, "times to echo the input")

    var rootCmd = &cobra.Command{Use: "app"}
    rootCmd.AddCommand(cmdPrint, cmdEcho)
    cmdEcho.AddCommand(cmdTimes)
    rootCmd.Execute()
}

但是,我已经为它制作了文件package main,我似乎无法使其正常工作.我知道rootCmd不是可执行的.但是,在我看来,Use字段表现不一致(据我所知).我试图了解命令如何在命令行中实际运行,并以不同的方式编译文件来试验它.

比如我编译这个文件,我命名为cobra.go用go build cobra.go,现在我有一个可执行文件cobra.

如果我这样做的./name行为./name help和打印方式相同:

Usage:
  app [command]

Available Commands:
  print [string to print]   Print anything to the screen
  echo [string to echo]     Echo anything to the screen
  help [command]            Help about any command

 Available Flags:
      --help=false: help for app

Use "app help [command]" for more information about that command.

但是,描述错误地说要使用它,你必须做"app help [command]".

如果我这样做./app help print(当然只有cobra可执行文件)它打印:

zsh: no such file or directory: ./app

如果我这样做app help print也不起作用(因为它没有在PATH中找到):

zsh: command not found: app

所以我的理解是,除非我使用与root相同的名称构建它,否则cobra会表现得很有趣.

因此,这意味着use字段必须匹配帮助输出的文件名才有意义,并且我们能够正确运行其子命令,对吧？

此外,如何是一个能够有(编译)多个不同的"根"在同一个项目的命令,如果只有一个主包允许？如果在main下有多个"root"命令,它应该不起作用,对吧？我很快就会尝试其中的一些想法.