Symfony2 - 以编程方式设置记住我的cookie

我已经通过新的simple_form functionnality实现了自定义身份验证器

    main:
        pattern: ^/
        simple_form:
            authenticator: custom_authenticator
            provider: fos_userbundle
            csrf_provider: form.csrf_provider
        remember_me:
            key:      "%secret%"
            lifetime: 31536000 # 365 jours
            path:     /
            domain:   ~
            name: my_remember_cookie

我的Authenticator中的authenticateToken()方法如下所示:

try {
    $user = $userProvider->loadUserByUsername($token->getUsername());
} catch (UsernameNotFoundException $e) {
    throw new AuthenticationException('Unknown user');
}
if ($user->isLocked() === true) {
    throw new AuthenticationException('User locked');
}
if (/* Logic checks */) { 
    return new UsernamePasswordToken(
            $user, null, $providerKey, $user->getRoles()
    );
}

我想知道,从这一点来说,是否有一种方法以编程方式设置记住我的cookie(在我的情况下,我想根据用户的角色设置它)？

编辑:我解决了它感谢sebbo,重点是在将请求对象传递给rememberMe服务之前手动设置$ request对象中的remember_me参数.

我的最终代码:

/**
 * onAuthenticationSuccess
 * 
 * @param     Request $request
 * @param     TokenInterface $token
 * @return     Response
 */
public function onAuthenticationSuccess(Request $request, TokenInterface $token) {
    $url = $this->container->get("session")->get('_security.main.target_path') ? $this->container->get("session")->get('_security.main.target_path') : $this->container->get("router")->generate('home');
    $response = $request->isXmlHttpRequest() ?
            new JsonResponse(array(
                "success" => true,
                "url" => $url
            )) : new RedirectResponse($url);
    // Relevant part
    $rememberMeService = $this->container->get("EDE.security.service.remember_me");
    $request->attributes->set($rememberMeService->getRememberMeParameter(), 'true'/*set to other than 'yes'|'true'|'on'|'1' to force to don't set cookie*/);
    $rememberMeService->loginSuccess($request, $response, $token);
    return $response;
}

服务别名:

手动请求参数分配似乎有点脏,但它的工作原理.