问

使用JsonView Jackson的Json序列化

手机用户2602890681 发布于 2023-01-06 16:12

static

我有一个类,我想序列化忽略一些属性

public class User extends Model
{
    static class publicView{}

    @JsonView(publicView.class)
    private Long id;

    private String showName;

    @JsonView(publicView.class)
    private List callableQueues;

}

当我在没有JsonView的情况下进行序列化时,我通常会做这样的事情

public JsonNode jsonSerialization()
{
    ObjectMapper mapper = new ObjectMapper();
    return mapper.convertValue(this, JsonNode.class);  
}

如何使用"publicView"类进行序列化？

1 个回答

您可以配置对象映射器以包括publicView.class和排除其他字段,如下所示:

禁用MapperFeature.DEFAULT_VIEW_INCLUSION映射器功能.

通过该ObjectMapper#getSerializationConfig().withView()方法启用序列化视图.

请参阅此页面以供参考.

这是一个例子:

public class JacksonView1 {
    public static class publicView{}

    public static class User  {
        public User(Long id, String showName, List<String> callableQueues) {
            this.id = id;
            this.showName = showName;
            this.callableQueues = callableQueues;
        }
        @JsonView(publicView.class)
        public final Long id;

        public final String showName;

        @JsonView(publicView.class)
        public final List<String> callableQueues;
    }

    public static void main(String[] args) {
        User user = new User(123l, "name", Arrays.asList("a", "b"));
        ObjectMapper mapper = new ObjectMapper();
        mapper.disable(MapperFeature.DEFAULT_VIEW_INCLUSION);
        mapper.setConfig(mapper.getSerializationConfig()
                .withView(publicView.class));
        System.out.println(mapper.convertValue(user, JsonNode.class));
    }
}

输出:

{"id":123,"callableQueues":["a","b"]}

2023-01-06 16:16 回答

林白LS

撰写答案

今天，你开发时遇到什么问题呢？

立即提问

热门标签