使用常见OpenOption组合的最快方法

这些都是您的轻松可能性.

静态导入,以提高可读性:

import static java.nio.file.StandardOpenOption.CREATE_NEW;
import static java.nio.file.StandardOpenOption.WRITE;

OpenOption[] options = new OpenOption[] { WRITE, CREATE_NEW };

使用默认值:

     //no Options anyway
     Files.newBufferedReader(path, cs)

     //default: CREATE, TRUNCATE_EXISTING, and WRITE not allowed: READ
     Files.newBufferedWriter(path, cs, options)

     //default: READ not allowed: WRITE
     Files.newInputStream(path, options)

     //default: CREATE, TRUNCATE_EXISTING, and WRITE not allowed: READ
     Files.newOutputStream(path, options)

     //default: READ do whatever you want
     Files.newByteChannel(path, options)

最后,可以指定这样的选项集:

     Files.newByteChannel(path, EnumSet.of(CREATE_NEW, WRITE));

我能提供的最好的建议是欺骗T ...和T []的等价,其中一个其他stackoverflow讨论说应该工作

我可以将数组作为参数传递给Java中带有变量参数的方法吗？

所以...

OpenOption myOptions[] = {StandardOpenOption.WRITE, StandardOpenOption.CREATE, StandardOpenOption.TRUNCATE_EXISTING};
OutputStream foo=OutputStream.newOutputStream(myPath,myOptions);

警告:未经测试.