如何在Swift中连接字符串？

您可以通过多种方式连接字符串:

let a = "Hello"
let b = "World"

let first = a + ", " + b
let second = "\(a), \(b)"

你也可以这样做:

var c = "Hello"
c += ", World"

我相信还有更多方法.

一点描述

let创造一个常数.(有点像NSString).设置后,您无法更改其值.您仍然可以将其添加到其他内容并创建新变量.

var创建一个变量.(有点像NSMutableString)所以你可以改变它的价值.但是Stack Overflow已经多次回答了这个问题(参见let和var之间的区别).

注意

在现实中let,并var有很大的不同,从NSString和NSMutableString,但它可以帮助类比.

您可以通过以下方式添加字符串:

str += ""

str = str + ""

str = str + str2

str = "" + ""

str = "\(variable)"

str = str + "\(variable)"

我想我把它们都命名了.

let the_string = "Swift"
let resultString = "\(the_string) is a new Programming Language"

var language = "Swift" 
var resultStr = "\(language) is a new programming language"

这也可以:

var string = "swift"
var resultStr = string + " is a new Programming Language"

XCode不接受使用普通字符串添加的可选字符串.我写了这个扩展来解决这个问题:

extension String {
    mutating func addString(str: String) {
        self = self + str
    }
}

然后你可以这样称呼它:

var str1: String?
var str1 = "hi"
var str2 = " my name is"
str1.addString(str2)
println(str1) //hi my name is

但是你现在也可以这样做:

var str1: String?
var str1 = "hi"
var str2 = " my name is"
str1! += str2

非常简单:

let StringA = "Hello"
let StringB = "World"
let ResultString = "\(StringA)\(StringB)"
println("Concatenated result = \(ResultString)")

\这用于将一个字符串附加到另一个字符串.

var first = "Hi" 
var combineStr = "\(first) Start develop app for swift"

您也可以尝试: - +关键字.

 var first = "Hi" 
 var combineStr = "+(first) Start develop app for swift"

试试这个代码.

您现在可以在Swift中使用stringByAppendingString.

var string = "Swift"
var resultString = string.stringByAppendingString(" is new Programming Language")