问

如何通过Python defaultdict迭代？

手机用户2702935897 发布于 2023-01-18 09:27

default

我有一本看起来像这样的字典.

defaultdict(,
{
 2012: [Counter({1: 1, 2: 1, 4: 1}), 3],
 2013: [Counter({4: 2, 12: 1, 5: 1, 6: 1}), 5],
 2014: [Counter({4: 3, 1: 1, 2: 1, 3: 1}), 6]}
)

我试图通过Counter dict迭代.像这样.

这是我试过的代码.

for key, value in d.iteritems():
    for k, v in value:
        print k, v

这是错误:

Traceback (most recent call last):
  File "C:/test.py", line 42, in 
    for k, v in value:
ValueError: too many values to unpack

JINJA2解决方案:

{% extends "base.html" %}
{% block title %}Archive{% endblock %}
{% block content %}


{% for key, value in d.iteritems() %}
    {{ key }} ({{ value[1] }})
    {% for m, c in value[0].items() %}
       {{m|month_number}} ({{ c }})
        {{ a }}
    {% endfor %}
{% endfor %}

{%endblock%}

1 个回答

>>> for year, (counter, other_thing) in d.items():
...     print(year)
...     for k, v in counter.items():
...         print(k, v)
...     print(other_thing)
...     print()
...     
2012
1 1
2 1
4 1
3

2013
4 2
12 1
5 1
6 1
5

2014
1 1
2 1
3 1
4 3
6

2023-01-18 09:29 回答

php程序小哥

撰写答案

今天，你开发时遇到什么问题呢？

立即提问

热门标签