问

如何使用Guzzle以JSON格式发送POST请求？

两斤发布于 2023-01-19 14:39

post

有没有人知道post使用JSON 的正确方法Guzzle？

$request = $this->client->post(self::URL_REGISTER,array(
                'content-type' => 'application/json'
        ),array(json_encode($_POST)));

我收到internal server error服务器的回复.它适用于Chrome Postman.

7 个回答

简单而基本的方式(guzzle6):

$client = new Client([
    'headers' => [ 'Content-Type' => 'application/json' ]
]);

$response = $client->post('http://api.com/CheckItOutNow',
    ['body' => json_encode(
        [
            'hello' => 'World'
        ]
    )]
);

要获取响应状态代码和正文的内容,我执行了以下操作:

echo '<pre>' . var_export($response->getStatusCode(), true) . '</pre>';
echo '<pre>' . var_export($response->getBody()->getContents(), true) . '</pre>';

2023-01-19 14:41 回答

那些触动你的回忆

对于Guzzle <= 4:

这是一个原始的帖子请求,因此将JSON放入正文解决了问题

$request = $this->client->post($url,array(
                'content-type' => 'application/json'
        ),array());
$request->setBody($data); #set body!
$response = $request->send();

return $response;

2023-01-19 14:41 回答

超级神棍小虾米

这对我有用(使用Guzzle 6)

$client = new Client(); 
$result = $client->post('http://api.example.com', [
            'json' => [
                'value_1' => 'number1',
                'Value_group' =>  
                             array("value_2" => "number2",
                                    "value_3" => "number3")
                    ]
                ]);

echo($result->getBody()->getContents());

2023-01-19 14:41 回答

YANLIUPING

对于Guzzle 5和6,您可以这样做:

use GuzzleHttp\Client;

$client = new Client();

$response = $client->post('url', [
    GuzzleHttp\RequestOptions::JSON => ['foo' => 'bar']
]);

文件

2023-01-19 14:41 回答

美好时光33_862

Guzzle 6.2对我有用:

$gClient =  new \GuzzleHttp\Client(['base_uri' => 'www.foo.bar']);
$res = $gClient->post('ws/endpoint',
                            array(
                                'headers'=>array('Content-Type'=>'application/json'),
                                'json'=>array('someData'=>'xxxxx','moreData'=>'zzzzzzz')
                                )
                    );

根据文档guzzle做json_encode

2023-01-19 14:41 回答

wang小资_588

$client = new \GuzzleHttp\Client();

$body['grant_type'] = "client_credentials";
$body['client_id'] = $this->client_id;
$body['client_secret'] = $this->client_secret;

$res = $client->post($url, [ 'body' => json_encode($body) ]);

$code = $res->getStatusCode();
$result = $res->json();

2023-01-19 14:41 回答

MySeptember

$client = new \GuzzleHttp\Client(['base_uri' => 'http://example.com/api']);

$response = $client->post('/save', [
    'json' => [
        'name' => 'John Doe'
    ]
]);

return $response->getBody();

2023-01-19 14:43 回答

大侠aaaaaaaaaaa_225

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