我知道如何绘制弧线
我还发现了如何从这里绘制渐变线 我发现两个函数可以绘制渐变:CGContextDrawLinearGradient和CGContextDrawRadialGradient.but如何绘制渐变弧?我想像这张照片一样意识到:
derekahc.. 8
我花了很长时间寻找如何做到这一点,所以我想我会发布我最终做的方式.事实证明,这两个答案都是这个问题的优秀答案:
从圆圈或圆环画出片段
出于我的目的,我只使用了答案的绘图和渐变部分.结构看起来或多或少像这样......
CGContextRef context = UIGraphicsGetCurrentcontext(); CGFloat arcStartAngle = M_PI; CGFloat arcEndAngle = 2 * M_PI; CGPoint startPoint = CGPointMake(...); CGPoint endPoint = CGPointMake(...); CGColorSpaceRef colorSpace = CGColorSpaceCreateDeviceRGB(); CGFloat colors[] = { 1.0, 0.0, 0.0, 1.0, //RGBA values (so red to green in this case) 0.0, 1.0, 0.0, 1.0 }; CGGradientRef gradient = CGGradientCreateWithColorComponents(colorSpace, colors, NULL, 2); //Where the 2 is for the number of color components. You can have more colors throughout //your gradient by adding to the colors[] array, and changing the components value. CGColorSpaceRelease(colorSpace); //Now for the arc part... CGMutablePathRef arc = CGPathCreateMutable(); CGPathMoveToPoint(arc, NULL, startPoint.x, startPoint.y); //Here, the CGPoint self.arcCenter is the point around which the arc is placed, so maybe the //middle of your view. self.radius is the distance between this center point and the arc. CGPathAddArc(arc, NULL, self.arcCenter.x, self.arcCenter.y, self.radius, arcStartAngle, arcEndAngle, YES); //This essentially draws along the path in an arc shape CGPathRef strokedArc = CGPathCreateCopyByStrokingPath(arc, NULL, 5.0f, kCGLineCapButt, kCGLineJoinMiter, 10); CGContextSaveGState(context); CGContextAddPath(context, strokedArc); CGContextClip(context); CGContextDrawLinearGradient(context, gradient, startPoint, endPoint, 0); CGContextDrawPath(context, kCGPathFillStroke); CGGradientRelease(gradient); CGContextRestoreGState(context); //This all draws a gradient that is much larger than the arc itself, but using //CGContextClip, it clips out everything EXCEPT the colors in the arc. Saving and Restoring //the state allows you to preserve any other drawing going on. If you didn't use these, //then all other drawing would also be clipped.
我希望这有帮助.如果其中任何一项不清楚,我建议您查看上面的问题链接.这些问题的答案包含了我在这个答案中使用的所有内容以及一些更酷和有用的绘图技巧.