如何检查元素是否在嵌套列表中？

循环遍历嵌套列表并测试它们; 该any()功能使这个效率:

def nested(x, ys):
    return any(x in nested for nested in ys)

此假设ys仅嵌套到一个级别.

如果需要递归,您可以使用:

def flatten(lst):
    for elem in lst:
        if isinstance(elem, (list, tuple)):
            for nested in flatten(elem):
                yield nested
        else:
            yield elem

def nested(x, ys):
    return any(x == nested for nested in flatten(ys))

我使用了简化测试,list并且tuple只是为了避免"扁平化"字符串.