问

Python:如果变量是整数或浮点数,则为真

一切近乎完美发布于 2023-01-18 09:22

我正在尝试从书籍作业中编写一个小程序,但是我在检测用户输入是否为int/float(增加到总数)或string(return error)时遇到问题.我尝试在add_to_total变量上使用.isdigit()但是当我键入float时,它会直接跳到else代码块.我试过在网上搜索但找不到明确的答案.这是我的代码:

total = 0
print("Welcome to the receipt program!")

while True:
    add_to_total = raw_input("Enter the value for the seat ['q' to quit]: ")
    if add_to_total == 'q':
        print("*****")
        print "Total: $%s" % total
        break
    if add_to_total.isdigit(): #Don't know how to detect if variable is int or float at the same time.
        add_to_total = float(add_to_total)
        total += add_to_total
    else:
        print "I'm sorry, but '%s' isn't valid. Please try again." % add_to_total

任何答案将不胜感激.

2 个回答

使用异常来捕获无法汇总的用户输入.从测试任何用户输入切换到仅保护数学运算以总结收据.

total = 0
print("Welcome to the receipt program!")

while True:
    add_to_total = raw_input("Enter the value for the seat ['q' to quit]: ")
    if add_to_total == 'q':
        break
    try:
        total += float(add_to_total)
    except ValueError:
        print "I'm sorry, but '%s' isn't valid. Please try again." % add_to_total
print("*****")
print "Total: $%s" % total


                
                    2023-01-18 09:24  回答
                       xzh


                        
                您始终可以使用该try... except方法:

try:
    add_to_total = float(add_to_total)
except ValueError:
    print "I'm sorry, but '%s' isn't valid. Please try again." % add_to_total
else:
    total += add_to_total


请记住:请求宽恕比获得更容易

        
                
                    2023-01-18 09:27  回答
                       密歇根的闪闪



    
    
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