问

警告:尝试在视图不在窗口层次结构中显示on - swift

mobiledu2502890207 发布于 2022-12-19 19:19

view

我试图提出一个数据模型中ViewController 是否有任何已保存的数据.但是我收到以下错误:

警告:尝试显示其视图不在窗口层次结构中的*on*

相关代码:

override func viewDidLoad() {
    super.viewDidLoad()
    loginButton.backgroundColor = UIColor.orangeColor()

    var request = NSFetchRequest(entityName: "UserData")
    request.returnsObjectsAsFaults = false

    var appDel:AppDelegate = (UIApplication.sharedApplication().delegate as AppDelegate)
    var context:NSManagedObjectContext = appDel.managedObjectContext!

    var results:NSArray = context.executeFetchRequest(request, error: nil)!

    if(results.count <= 0){
        print("Inga resultat")
    } else {
        print("SWITCH VIEW PLOX")
        let internVC = self.storyboard?.instantiateViewControllerWithIdentifier("internVC") as internViewController
        self.presentViewController(internVC, animated: true, completion: nil)
    }
}

我尝试过使用谷歌找到的不同解决方案但没有成功.

7 个回答

在目标c:当在mpmovieplayer上呈现viewcontroller时,这解决了我的问题

- (UIViewController*) topMostController
{
    UIViewController *topController = [UIApplication sharedApplication].keyWindow.rootViewController;

    while (topController.presentedViewController) {
        topController = topController.presentedViewController;
    }

    return topController;
}

2022-12-19 19:20 回答

斯威夫特3

我有这个不断出现作为一个新手,并发现当前加载模态视图,可以被解雇,但切换到根控制器是最好的,如果你不需要显示模态.

我正在使用它

let storyboard = UIStoryboard(name: "Main", bundle: nil)
let vc  = storyboard?.instantiateViewController(withIdentifier: "MainAppStoryboard") as! TabbarController
present(vc, animated: false, completion: nil)

使用它来代替我的tabController:

let storyboard = UIStoryboard(name: "Main", bundle: nil)
let view = storyboard.instantiateViewController(withIdentifier: "MainAppStoryboard") as UIViewController
let appDelegate = UIApplication.shared.delegate as! AppDelegate
//show window
appDelegate.window?.rootViewController = view

如果您需要在多个故事板屏幕之间切换,只需调整到视图控制器即可.

2022-12-19 19:20 回答

所谓-旧

你只需要执行一个延迟选择器 - (0秒工作).

override func viewDidLoad() {
    super.viewDidLoad()
    perform(#selector(presentExampleController), with: nil, afterDelay: 0)
}

@objc private func presentExampleController() {
    let exampleStoryboard = UIStoryboard(named: "example", bundle: nil)
    let exampleVC = storyboard.instantiateViewController(withIdentifier: "ExampleVC") as! ExampleVC
    present(exampleVC, animated: true) 
}

2022-12-19 19:21 回答

lovejiao2012

此时,在代码中,视图控制器的视图仅已创建,但未添加到任何视图层次结构中.如果你想尽快从那个视图控制器出现,你应该做到viewDidAppear最安全.

2022-12-19 19:21 回答

霍邱宋涛_842

对于SWIFT

func topMostController() -> UIViewController {
    var topController: UIViewController = UIApplication.sharedApplication().keyWindow!.rootViewController!
    while (topController.presentedViewController != nil) {
        topController = topController.presentedViewController!
    }
    return topController
}

2022-12-19 19:21 回答

手机用户2502939965

斯威夫特3.

调用此函数以获取最顶层的视图控制器,然后使该视图控制器存在.

func topMostController() -> UIViewController {
    var topController: UIViewController = UIApplication.shared.keyWindow!.rootViewController!
        while (topController.presentedViewController != nil) {
            topController = topController.presentedViewController!
        }
        return topController
    }

用法:

let topVC = topMostController()
let vcToPresent = self.storyboard!.instantiateViewController(withIdentifier: "YourVCStoryboardID") as! YourViewController
topVC.present(vcToPresent, animated: true, completion: nil)

2022-12-19 19:21 回答

手机用户2602931437

斯威夫特4

func topMostController() -> UIViewController {
    var topController: UIViewController = UIApplication.shared.keyWindow!.rootViewController!
    while (topController.presentedViewController != nil) {
        topController = topController.presentedViewController!
    }
    return topController
}

2022-12-19 19:21 回答

可靠的我还是一个人

撰写答案

今天，你开发时遇到什么问题呢？

立即提问

热门标签

警告:尝试在视图不在窗口层次结构中显示*on* - swift

警告:尝试在视图不在窗口层次结构中显示on - swift