多次抛出异常会丢失其原始堆栈跟踪

我一直在玩Exceptions以了解我应该如何正确使用它们.到目前为止,我知道throw保持原始堆栈跟踪; throw new CustomException(...)通常用于想要添加有关发生的异常的更多信息或添加/更改消息,甚至更改异常本身的类型; 并且throw ex永远也不会被使用,除非我不想失去原来的堆栈跟踪.

所以我编写了一个小程序,我可以在原始消息中添加内容时多次捕获并重新抛出异常.

public class Sample
{
    static void Main(string[] args)
    {
        new Tester().FirstCall();
    }
}

public class Tester
{
    public void FirstCall()
    {
        try
        {
            SecondCall();
        }
        catch (Exception e)
        {
            Console.WriteLine(e.StackTrace);
            Console.WriteLine(e.Message);
        }
    }

    public void SecondCall()
    {
        try
        {
            ThirdCall();
        }
        catch (GoodException ex)
        {
            throw new Exception(ex.Message, ex);
        }
    }

    public void ThirdCall()
    {
        try
        {
            FourthCall();
        }
        catch (ArithmeticException ae)
        {
            throw new GoodException("Arithmetic mistake: " + ae.Message, ae);
        }
    }

    public void FourthCall()
    {
        int d = 0;
        int x = 10 / d;
    }
}

哪里GoodException是一个自定义异常正确实施.

我期待控制台显示如下内容:

   at PlayingWithExceptions.Tester.FourthCall() in d:\Projects\PlayingWithExceptions\PlayingWithExceptions\Trying.cs:line 67
   at PlayingWithExceptions.Tester.ThirdCall() in d:\Projects\PlayingWithExceptions\PlayingWithExceptions\Trying.cs:line 59
   at PlayingWithExceptions.Tester.SecondCall() in d:\Projects\PlayingWithExceptions\PlayingWithExceptions\Trying.cs:line 41
   at PlayingWithExceptions.Tester.FirstCall() in d:\Projects\PlayingWithExceptions\PlayingWithExceptions\Trying.cs:line 25
Arithmetic mistake: Attempted to divide by zero.

但相反,我得到了这个:

   at PlayingWithExceptions.Tester.SecondCall() in d:\Projects\PlayingWithExceptions\PlayingWithExceptions\Trying.cs:line 41
   at PlayingWithExceptions.Tester.FirstCall() in d:\Projects\PlayingWithExceptions\PlayingWithExceptions\Trying.cs:line 25
Arithmetic mistake: Attempted to divide by zero.

出于某种原因,它只能进行第二次调用.即使我将捕获的异常作为一个传递InnerException,堆栈跟踪仍然丢失.我知道如果我只是编写throw而不是抛出一个新的异常,我可以保留原始的堆栈跟踪,但如果我这样做,我将无法更改原始消息(这是本练习的全部内容) .

所以我的问题是,我该怎么做才能更改Exception消息并保持原始堆栈跟踪的方式？

编辑:由于异常不应该使用逻辑控制并且只捕获一次,保持原始堆栈跟踪并显示新消息的正确方法是将FourthCall包装在try/catch中(其中生成带有消息的新Exception) ),并且只在FirstCall中一次捕获它.